Andrew's computer hard drive has a memory capacity of 1 terabyte, which is \( 10^{12} \) bytes. If the size of an image is \( 5 \times 10^{6} \) bytes, what is the maximum number of such images that can be saved on Andrew's hard drive?
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To find the maximum number of images that can be saved on Andrew's hard drive, we need to divide the total capacity of the hard drive by the size of one image. The capacity of the hard drive is \( 1 \, \text{TB} = 10^{12} \, \text{bytes} \), and the size of one image is \( 5 \times 10^{6} \, \text{bytes} \). So, the calculation will be: \[ \text{Maximum number of images} = \frac{10^{12}}{5 \times 10^{6}} = \frac{10^{12}}{5 \times 10^{6}} = \frac{10^{12}}{5 \cdot 10^{6}} = \frac{10^{12}}{5 \cdot 10^{6}} \cdot \frac{1}{10^{6}} = \frac{10^{12-6}}{5} = \frac{10^{6}}{5} \] Calculating that gives: \[ = 2 \times 10^{5} = 200000 \] Therefore, the maximum number of images that can be saved on Andrew's hard drive is **200,000 images**.