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Andrew's computer hard drive has a memory capacity of 1 terabyte, which is \( 10^{12} \) bytes. If the size of an image is \( 5 \times 10^{6} \) bytes, what is the maximum number of such images that can be saved on Andrew's hard drive?

Ask by Todd Gordon. in the United States
Jan 23,2025

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Answer

Andrew can store 200,000 images on his 1 terabyte hard drive.

Solution

To determine the maximum number of images Andrew can store on his 1 terabyte (TB) hard drive, follow these steps: 1. **Understand the Units:** - **1 terabyte (TB)** = \( 10^{12} \) bytes - **Size of one image** = \( 5 \times 10^{6} \) bytes 2. **Calculate the Number of Images:** To find out how many images can fit into 1 TB, divide the total storage capacity by the size of one image: \[ \text{Number of images} = \frac{\text{Total Storage}}{\text{Size per Image}} = \frac{10^{12} \text{ bytes}}{5 \times 10^{6} \text{ bytes}} \] 3. **Perform the Division:** \[ \frac{10^{12}}{5 \times 10^{6}} = \frac{10^{12}}{5 \times 10^{6}} = \frac{10^{12}}{5 \times 10^{6}} = 2 \times 10^{5} = 200,\!000 \] 4. **Conclusion:** Andrew can store **200,000** such images on his 1 TB hard drive. **Final Answer:** A maximum of 200 000 images can be saved on Andrew’s 1 terabyte hard drive.

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To find the maximum number of images that can be saved on Andrew's hard drive, we need to divide the total capacity of the hard drive by the size of one image. The capacity of the hard drive is \( 1 \, \text{TB} = 10^{12} \, \text{bytes} \), and the size of one image is \( 5 \times 10^{6} \, \text{bytes} \). So, the calculation will be: \[ \text{Maximum number of images} = \frac{10^{12}}{5 \times 10^{6}} = \frac{10^{12}}{5 \times 10^{6}} = \frac{10^{12}}{5 \cdot 10^{6}} = \frac{10^{12}}{5 \cdot 10^{6}} \cdot \frac{1}{10^{6}} = \frac{10^{12-6}}{5} = \frac{10^{6}}{5} \] Calculating that gives: \[ = 2 \times 10^{5} = 200000 \] Therefore, the maximum number of images that can be saved on Andrew's hard drive is **200,000 images**.

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