Question
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Fathur bought a number of stickers. He sold \( \frac{4}{5} \) of the stickers and lost \( \frac{1}{2} \) of the remainder bowhowin If he had 480 sticters, how Many stickers did he have at first?

Ask by Hammond Lee. in Singapore
Jan 23,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

Fathur initially had 4,800 stickers.

Solution

Let's break down the problem step by step: 1. **Let the initial number of stickers be \( x \).** 2. **Stickers Sold:** - Fathur sold \( \frac{4}{5} \) of his stickers. - So, the number of stickers sold is \( \frac{4}{5}x \). 3. **Stickers Remaining After Sale:** - After selling, he has \( x - \frac{4}{5}x = \frac{1}{5}x \) stickers remaining. 4. **Stickers Lost:** - He lost \( \frac{1}{2} \) of the remaining stickers. - So, the number of stickers lost is \( \frac{1}{2} \times \frac{1}{5}x = \frac{1}{10}x \). 5. **Final Number of Stickers:** - After losing some stickers, he has \( \frac{1}{5}x - \frac{1}{10}x = \frac{1}{10}x \) stickers left. 6. **Given Final Stickers:** - It's given that he has 480 stickers at the end. - So, \( \frac{1}{10}x = 480 \). 7. **Solving for \( x \):** \[ x = 480 \times 10 = 4800 \] **Therefore, Fathur initially had 4,800 stickers.** Answer: Fathur originally had 4 800 stickers.

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Extra Insights

Ah, math problems can be like little puzzles! Let's break it down. Fathur originally had 480 stickers. If he sold \( \frac{4}{5} \) of them, he sold \( \frac{4}{5} \times 480 = 384 \) stickers. Now, let's find out how many he had left: \( 480 - 384 = 96 \) stickers. He then lost \( \frac{1}{2} \) of that remainder, which is \( \frac{1}{2} \times 96 = 48 \). So at the end, he has \( 96 - 48 = 48 \) stickers left! Thus, Fathur had **480 stickers** at first. To double-check, subtract everything step-by-step and ensure that the fractions were correctly calculated while keeping a close eye on how many remain after both selling and losing stickers! Sometimes, stepping away and coming back helps clear the confusion.

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