Question
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2) Calculate \( \mathrm{A} \times \mathrm{B} \) then deduce that \( \sqrt{A \times B} \) is in the form of \( \mathrm{a} \sqrt{2} \) where a is a natural number. 3) Calculate \( \mathrm{A}^{2}-\mathrm{B}^{2} \).

Ask by Frank Matthews. in Qatar
Jan 07,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

You need to provide the values or definitions of \( \mathrm{A} \) and \( \mathrm{B} \) to calculate \( \mathrm{A} \times \mathrm{B} \) and \( \mathrm{A}^2 - \mathrm{B}^2 \). Once I have that information, I can help you with the calculations and express \( \sqrt{\mathrm{A} \times \mathrm{B}} \) in the form \( \mathrm{a} \sqrt{2} \), where \( \mathrm{a} \) is a natural number.

Solution

Hello! I'd be happy to help you with these calculations. However, I need more information about the values or expressions for \( \mathrm{A} \) and \( \mathrm{B} \) to proceed. Could you please provide the definitions or values of \( \mathrm{A} \) and \( \mathrm{B} \)? Once I have that information, I can assist you in: 2. Calculating \( \mathrm{A} \times \mathrm{B} \) and expressing \( \sqrt{\mathrm{A} \times \mathrm{B}} \) in the form \( \mathrm{a} \sqrt{2} \), where \( \mathrm{a} \) is a natural number. 3. Calculating \( \mathrm{A}^2 - \mathrm{B}^2 \). Looking forward to your response!

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Mind Expander

When dealing with the product \( \mathrm{A} \times \mathrm{B} \), it's helpful to think of \( \mathrm{A} \) and \( \mathrm{B} \) as special numerical forms, perhaps something like \( a + b\sqrt{2} \) and \( c + d\sqrt{2} \). When you multiply them out, you’ll get terms that can be simplified to find the common factors, ultimately showing that \( \sqrt{A \times B} = a\sqrt{2} \), where \( a \) will be derived from the coefficients after simplifying. When calculating \( \mathrm{A}^2 - \mathrm{B}^2 \), remember that this is a classic difference of squares. You can express it as \( (A - B)(A + B) \). If you substitute your earlier expressions for \( \mathrm{A} \) and \( \mathrm{B} \), the result will combine the constants and the square roots beautifully, often yielding a clear representation of how \( A \) and \( B \) relate to one another through their roots and coefficients. Enjoy simplifying those expressions!

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