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A body moved at a constant speed, covering 150 meters in 10 seconds, then returning to the starting point in 30 seconds. Calculate the average speed of this body during the return trip.

Ask by Mills Joseph. in Egypt
Jan 22,2025

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Answer

The average speed during the return trip is 5 meters per second.

Solution

To calculate the **average speed** of the body during the **return trip**, we can use the basic formula for speed: \[ \text{Speed} = \frac{\text{Distance}}{\text{Time}} \] ### Given: - **Distance of return trip**: 150 meters - **Time taken for return trip**: 30 seconds ### Calculation: \[ \text{Average Speed} = \frac{150 \, \text{meters}}{30 \, \text{seconds}} = 5 \, \text{meters/second} \] ### Conclusion: The average speed of the body during the return trip is **5 meters per second (m/s)**.

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To find the average speed during the return trip, we need to consider the total distance covered and the time taken. The body returned to the starting point over a distance of 150 meters in 30 seconds. Thus, the average speed can be calculated using the formula: Average Speed = Total Distance / Total Time Here, Total Distance = 150 meters, and Total Time = 30 seconds. So, the average speed during the return trip is: Average Speed = 150 m / 30 s = 5 m/s. The average speed of the body during the return trip is 5 meters per second. Now, let's think about how average speed differs from instantaneous speed—while you might be zooming at 15 m/s at a certain moment, if you take a long detour, your average speed at the end could be significantly lower. It’s all about how you measure time and distance! Did you know that in physics, the concept of average speed is fundamental for understanding motion? It’s essential not just for academic purposes, but for countless real-life applications—from planning your travel times to ensuring vehicles adhere to speed limits. A solid grasp of these principles can greatly enhance your daily decision-making and time management skills!

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