Let \( f(x)=\frac{3}{4} x+10 \) \( \quad g(x)=x^{2}-3 \) (8) at is the value of \( f(-2-g(3)) \) ?
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To find the value of \( f(-2-g(3)) \), we first need to calculate \( g(3) \). Starting with \( g(x) \): \[ g(x) = x^2 - 3 \] Now, substituting \( x = 3 \): \[ g(3) = 3^2 - 3 = 9 - 3 = 6 \] Next, we calculate \( -2 - g(3) \): \[ -2 - g(3) = -2 - 6 = -8 \] Now, we substitute this value into the function \( f(x) \): \[ f(x) = \frac{3}{4} x + 10 \] Substituting \( x = -8 \): \[ f(-8) = \frac{3}{4}(-8) + 10 = -6 + 10 = 4 \] Therefore, the value of \( f(-2-g(3)) \) is \( \boxed{4} \).