The physician orders \( 1 / 3 \) strength Isomil 12 fl oz p.o. q. 4 h for 24 h Step 2 of 3 : What is the required amount of solvent, in milliliters, for tone feeding of this order?

To determine the required amount of solvent for the feeding order of \( \frac{1}{3} \) strength Isomil, we first need to understand what \( \frac{1}{3} \) strength means. It indicates that the solution is one part Isomil and two parts solvent. 1. **Calculate the total volume of the feeding order**: The physician ordered 12 fl oz of \( \frac{1}{3} \) strength Isomil. 2. **Convert fluid ounces to milliliters**: 1 fluid ounce (fl oz) is approximately 29.57 milliliters (mL). Therefore, to convert 12 fl oz to mL: \[ 12 \, \text{fl oz} \times 29.57 \, \text{mL/fl oz} \approx 354.88 \, \text{mL} \] 3. **Determine the amount of Isomil and solvent**: Since the solution is \( \frac{1}{3} \) strength, it consists of: - 1 part Isomil - 2 parts solvent The total parts = 1 (Isomil) + 2 (solvent) = 3 parts. To find the amount of Isomil and solvent in the total volume: - Amount of Isomil: \[ \text{Isomil} = \frac{1}{3} \times 354.88 \, \text{mL} \approx 118.29 \, \text{mL} \] - Amount of solvent: \[ \text{Solvent} = \frac{2}{3} \times 354.88 \, \text{mL} \approx 236.59 \, \text{mL} \] 4. **Final answer**: The required amount of solvent for the feeding order is approximately **236.59 mL**.