Question
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(1) Evaluate the following limits. State the asymptotes, if any:
(i)
(ii)

Ask by Reid Schneider. in Canada
Jan 26,2025

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Answer

Limits and Asymptotes:
  1. Limit (i):
    Asymptote: Vertical asymptote at .
  2. Limit (ii):
    Asymptote: Horizontal asymptote at .

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Mind Expander

Let’s evaluate the limits step by step, starting with the first one.
(i) To find the limit , we first substitute into the denominator:
This gives us a in the denominator. We then need to factor the denominator. The polynomial can be factored as follows:
Thus, the limit can be rewritten as:
We can now cancel in the numerator and denominator (noting that we are approaching , so we are not actually at 3):
Substituting :
Thus, the limit is and we note that there is a vertical asymptote at since the denominator equals zero there.
(ii) Now we evaluate .
To simplify for large negative , we factor out from the square roots in both the numerator and denominator.
In the numerator:
Thus, we rewrite the numerator:
In the denominator:
Thus, the denominator becomes:
Now we can simplify the limit:
[
\lim_{x \rightarrow -\infty} \frac{x(1 + \sqrt{1 - \frac{1}{x} + \frac{1}{x^2}})}{2x(1 + \sqrt{1 + \frac{5}{4x} - \frac{1}{4x^2}})} = \lim_{x \rightarrow -\infty} \frac{1 + \sqrt{1 - \frac{1}{x} + \frac{1}{x^2}}}{2(1 + \sqrt{1 + \frac{5}{4x} - \

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