1. The G.C.F of the two numbers 5 and 8 is C. 80 50 A. 40 B. 12 2. \( \frac{1}{2}-\frac{1}{3}= \) C. \( \frac{2}{6} \) A. \( \frac{2}{5} \) B. \( \frac{1}{5} \) 3. The numeric expression which represents the double of the number 3 is D. \( \frac{1}{6} \) C. \( 3 \times 4 \) A. \( 3 \times 2 \) B. \( 3 \times 3 \) 4. The inequality "the number \( y \) is greater than or equal to -7 " can be wiritten as C. \( y \leq-7 \) D. 3 A. \( y>-7 \) B. \( y<-7 \) 5. The rational number \( -2 \frac{1}{4} \) in the form of \( \frac{a}{b} \) is C. \( y \leq-7 \) A. \( -\frac{7}{4} \) B. \( \frac{7}{4} \) C. \( -\frac{9}{4} \) 6. The range of the set of values: \( 3,2,5,5 \) and 9 is \( \qquad \) D. \( \frac{9}{4} \) C. 7 D. 9 A. 2 B. 5 7. The outlier of the set of values : \( 17,13,15,78 \) and 10 is \( \qquad \) A. 17 B. 13 C. 10 D. 78 2. Complete the following: 1. Distribute 18 biscuits and 12 chocolate equally in number of plates, then the greatast number of plates is \( \qquad \) \( 2.3+5 \times 2^{2}= \) \( \qquad \) 3. The algebraic expression of "add double of \( x \) to 3 " is \( \qquad \) 4. The number and its additive inverse at equal distance on the number line from \( \qquad \) 5. The algebraic equation of " \( y \) equals 4 subtracted from the number \( x \) " is \( \qquad \)
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Bonus Knowledge
Did you know that the concept of the greatest common factor (GCF) dates back to ancient mathematicians like Euclid? He introduced the Euclidean algorithm around 300 BC, which is an efficient method for finding the GCF of two numbers. So the next time you’re working out the GCF, you can thank centuries of mathematical ingenuity! When it comes to real-world applications, GCF can be super useful! For example, if you have 18 biscuits and 12 chocolates, and you want to distribute them evenly on plates, calculating the GCF (which is 6 in this case) helps you find the maximum number of plates you can use while ensuring both treats are equally distributed. Who doesn't want a perfect proportion of snacks at a party?