Question
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(b) \( \frac{2}{3}+\frac{3}{4} \)

Ask by Franklin Bird. in Germany
Jan 24,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

The sum is \( \frac{17}{12} \) or \( 1\frac{5}{12} \) or approximately \( 1.4166 \).

Solution

Calculate or simplify the expression \( \frac{2}{3}+\frac{3}{4} \). Calculate the value by following steps: - step0: Calculate: \(\frac{2}{3}+\frac{3}{4}\) - step1: Reduce fractions to a common denominator: \(\frac{2\times 4}{3\times 4}+\frac{3\times 3}{4\times 3}\) - step2: Multiply the numbers: \(\frac{2\times 4}{12}+\frac{3\times 3}{4\times 3}\) - step3: Multiply the numbers: \(\frac{2\times 4}{12}+\frac{3\times 3}{12}\) - step4: Transform the expression: \(\frac{2\times 4+3\times 3}{12}\) - step5: Multiply the numbers: \(\frac{8+3\times 3}{12}\) - step6: Multiply the numbers: \(\frac{8+9}{12}\) - step7: Add the numbers: \(\frac{17}{12}\) The sum of \( \frac{2}{3} \) and \( \frac{3}{4} \) is \( \frac{17}{12} \) or \( 1\frac{5}{12} \) or approximately \( 1.4166 \).

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Mind Expander

To add the fractions \( \frac{2}{3} \) and \( \frac{3}{4} \), first, find a common denominator, which is 12. Then, convert each fraction: \( \frac{2}{3} = \frac{8}{12} \) and \( \frac{3}{4} = \frac{9}{12} \). Now, add them together: \( \frac{8}{12} + \frac{9}{12} = \frac{17}{12} \). So, \( \frac{2}{3} + \frac{3}{4} = \frac{17}{12} \) or \( 1 \frac{5}{12} \). Also, this mathematical operation stems from the ancient Babylonians, who were some of the first to use fractions. They used a base-60 numeral system, so when you’re maneuvering through fractions today, remember the pioneering spirit of those early mathematicians who laid the groundwork for a system that still shapes our calculations! Want to avoid common pitfalls in adding fractions? Always ensure that your denominators are the same before combining. Many learners mistakenly add numerators first and forget that finding a common denominator is crucial. This small step can save you from unwittingly producing incorrect answers and demystifies the art of fraction addition!

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