raph the line with slope 3 passing through the point $$ (5,-5) $$.

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To graph the line with a slope of 3 that passes through the point $$ (5, -5) $$, we can use the point-slope form of the equation of a line, which is given by:

$$
y - y_1 = m(x - x_1)
$$

where $$ m $$ is the slope, and $$ (x_1, y_1) $$ is the point the line passes through. Here, $$ m = 3 $$, $$ x_1 = 5 $$, and $$ y_1 = -5 $$.

Substituting these values into the equation, we get:

$$
y - (-5) = 3(x - 5)
$$

This simplifies to:

$$
y + 5 = 3(x - 5)
$$

Now, distribute the 3 on the right side:

$$
y + 5 = 3x - 15
$$

Next, subtract 5 from both sides to solve for $$ y $$:

$$
y = 3x - 15 - 5
$$

$$
y = 3x - 20
$$

Now we have the equation of the line in slope-intercept form $$ y = mx + b $$, where $$ m = 3 $$ and $$ b = -20 $$.

### To graph the line:

1. **Plot the point $$ (5, -5) $$** on the coordinate plane.
2. **Use the slope**: From the point $$ (5, -5) $$, use the slope of 3 to find another point. The slope of 3 means that for every 1 unit you move to the right (positive x-direction), you move up 3 units (positive y-direction).
   - Starting from $$ (5, -5) $$:
     - Move 1 unit right to $$ (6, -5) $$.
     - Move up 3 units to $$ (6, -2) $$.
   - So, another point on the line is $$ (6, -2) $$.

3. **Draw the line**: Connect the points $$ (5, -5) $$ and $$ (6, -2) $$ with a straight line, and extend it in both directions.

### Summary:
The line with slope 3 passing through the point $$ (5, -5) $$ can be represented by the equation $$ y = 3x - 20 $$ and can be graphed by plotting the points and drawing a line through them.
The line with slope 3 passing through $$ (5, -5) $$ is represented by the equation $$ y = 3x - 20 $$.

raph the line with slope 3 passing through the point \( (5,-5) \).

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