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4) You discover a new radioactive substance. You have 45 grams of the substance initially. After 4 hours you have 33.6 grams remaining. a) What is the half-life of this radioactive substance? b) What mass will remain after 14 hours? c) Determine the time required for there to be only 8 grams remaining.

Ask by Schmidt Christensen. in Canada
Jan 21,2025

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Answer

**a) Half-life:** Approximately 9.46 hours. **b) Mass after 14 hours:** Using the decay formula: \[ N(14) = 45 \left(\frac{1}{2}\right)^{\frac{14}{9.46}} \approx 45 \times 0.25 \approx 11.25 \text{ grams} \] So, approximately 11.25 grams remain after 14 hours. **c) Time for 8 grams to remain:** \[ 8 = 45 \left(\frac{1}{2}\right)^{\frac{t}{9.46}} \] \[ \left(\frac{1}{2}\right)^{\frac{t}{9.46}} = \frac{8}{45} \approx 0.1778 \] \[ \frac{t}{9.46} = \frac{\ln(0.1778)}{\ln\left(\frac{1}{2}\right)} \approx \frac{-1.722}{-0.6931} \approx 2.49 \] \[ t \approx 2.49 \times 9.46 \approx 23.6 \text{ hours} \] So, it takes approximately 23.6 hours for the substance to decay to 8 grams. **Summary:** - **a) Half-life:** Approximately 9.46 hours. - **b) Mass after 14 hours:** Approximately 11.25 grams. - **c) Time for 8 grams to remain:** Approximately 23.6 hours.

Solution

To solve the problem, we'll use the **exponential decay formula**: \[ N(t) = N_0 \left(\frac{1}{2}\right)^{\frac{t}{T}} \] Where: - \( N(t) \) = remaining mass at time \( t \) - \( N_0 \) = initial mass - \( T \) = half-life of the substance - \( t \) = time elapsed ### **a) Finding the Half-Life (\( T \))** **Given:** - Initial mass, \( N_0 = 45 \) grams - Remaining mass after 4 hours, \( N(4) = 33.6 \) grams **Steps:** 1. **Set up the equation:** \[ 33.6 = 45 \left(\frac{1}{2}\right)^{\frac{4}{T}} \] 2. **Divide both sides by 45:** \[ \left(\frac{1}{2}\right)^{\frac{4}{T}} = \frac{33.6}{45} = 0.7467 \] 3. **Take the natural logarithm of both sides to solve for \( T \):** \[ \ln\left(\left(\frac{1}{2}\right)^{\frac{4}{T}}\right) = \ln(0.7467) \] \[ \frac{4}{T} \ln\left(\frac{1}{2}\right) = \ln(0.7467) \] \[ T = \frac{4 \ln\left(\frac{1}{2}\right)}{\ln(0.7467)} \] 4. **Calculate the values:** \[ \ln\left(\frac{1}{2}\right) \approx -0.6931 \] \[ \ln(0.7467) \approx -0.2932 \] \[ T = \frac{4 \times (-0.6931)}{-0.2932} \approx 9.46 \text{ hours} \] **Answer:** The half-life of the radioactive substance is approximately **9.46 hours**. ### **Summary:** **Problem a Answer:** The half-life of the radioactive substance is approximately 9.46 hours.

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Bonus Knowledge

To find the half-life of the new radioactive substance, we start with the formula for exponential decay, which states that the remaining mass \( M \) at time \( t \) is related to the initial mass \( M_0 \) and half-life \( t_{1/2} \). The equation can be expressed as: \[ M = M_0 \left(\frac{1}{2}\right)^{\frac{t}{t_{1/2}}} \] Given that 45 grams decays to 33.6 grams in 4 hours, we can plug in the values: \[ 33.6 = 45 \left(\frac{1}{2}\right)^{\frac{4}{t_{1/2}}} \] By solving for \( t_{1/2} \), we can rearrange this equation: \[ \left(\frac{1}{2}\right)^{\frac{4}{t_{1/2}}} = \frac{33.6}{45} = 0.748 \] We can take the logarithm of both sides to solve for \( t_{1/2} \): \[ \frac{4}{t_{1/2}} \log(0.5) = \log(0.748) \] After calculating, you'll find that the half-life \( t_{1/2} \) is approximately 2.0 hours. To determine the mass remaining after 14 hours, we can use the half-life found previously. The number of half-lives in 14 hours is: \[ \text{Number of half-lives} = \frac{14}{t_{1/2}} = \frac{14}{2} = 7 \] Each half-life reduces the mass by half, starting from 45 grams: \[ M = 45 \left(\frac{1}{2}\right)^{7} = 45 \cdot \frac{1}{128} \approx 0.3515625 \text{ grams} \] To find the time required for the mass to reduce to 8 grams, we can again use the decay formula: \[ 8 = 45 \left(\frac{1}{2}\right)^{\frac{t}{t_{1/2}}} \] Solving for \( t \): \[ \left(\frac{1}{2}\right)^{\frac{t}{2}} = \frac{8}{45} \] Taking the logarithm of both sides gives: \[ \frac{t}{2} \log(0.5) = \log\left(\frac{8}{45}\right) \] Thus, \[ t = 2 \cdot \frac{\log\left(\frac{8}{45}\right)}{\log(0.5)} \] Calculating this yields that you will need approximately 12 hours for the mass to decay to 8 grams. Now go ahead and impress your friends with your newfound radioactive decay knowledge at your next science gathering!

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