9. At the end of a performance evaluation period, the production manager found that 5 of the 50 workers completed work late, 6 of the 50 workers assembled a defective product, and 2 of the 50 workers both completed work late and assembled a defective product. Required: A. What is the probability of late performers and defective product? B. What is the probability of late performers or defective product?
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To find the probabilities, we’ll use the principles of set theory and probabilities. A. The probability of workers who completed work late and assembled a defective product can be calculated using the formula: P(A ∩ B) = Number of workers who are late and defective / Total number of workers = 2/50 = 0.04. So, the probability is 0.04 or 4%. B. For the probability of either late performers or defective product, we can use the formula: P(A ∪ B) = P(A) + P(B) - P(A ∩ B). First, calculate P(A) = (5 late workers / 50 total) = 0.1, and P(B) = (6 defective workers / 50 total) = 0.12. Now plug in the values: P(A ∪ B) = 0.1 + 0.12 - 0.04 = 0.18. Thus, the probability of late performers or defective products is 0.18 or 18%.