if $$ y=2 x^{2}+3 $$ Fill in the blank areas of the form $$ \mathbf{x} $$ 0 -2 12 2

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UpStudy AI · Accepted Answer

Certainly! Let's fill in the corresponding $$ y $$ values for each given $$ x $$ using the equation:

$$
y = 2x^{2} + 3
$$

### Calculation Steps:

1. **For $$ x = 0 $$:**
   $$
   y = 2(0)^{2} + 3 = 0 + 3 = 3
   $$

2. **For $$ x = -2 $$:**
   $$
   y = 2(-2)^{2} + 3 = 2(4) + 3 = 8 + 3 = 11
   $$

3. **For $$ x = 12 $$:**
   $$
   y = 2(12)^{2} + 3 = 2(144) + 3 = 288 + 3 = 291
   $$

4. **For $$ x = 2 $$:**
   $$
   y = 2(2)^{2} + 3 = 2(4) + 3 = 8 + 3 = 11
   $$

### Completed Table:

| $$ \mathbf{x} $$ | $$ y = 2x^{2} + 3 $$ |
|------------------|----------------------|
| 0                | 3                    |
| -2               | 11                   |
| 12               | 291                  |
| 2                | 11                   |

### Summary of $$ y $$ Values:

- $$ x = 0 $$   $$ y = 3 $$
- $$ x = -2 $$  $$ y = 11 $$
- $$ x = 12 $$  $$ y = 291 $$
- $$ x = 2 $$   $$ y = 11 $$

Feel free to let me know if you need further assistance or additional explanations!
Here are the $$ y $$ values for the given $$ x $$ values: - When $$ x = 0 $$, $$ y = 3 $$ - When $$ x = -2 $$, $$ y = 11 $$ - When $$ x = 12 $$, $$ y = 291 $$ - When $$ x = 2 $$, $$ y = 11 $$

if \( y=2 x^{2}+3 \) Fill in the blank areas of the form \( \mathbf{x} \) 0 -2 12 2

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