Question
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2. Fill in the blanks to write the factored form of \( y^{2}+11 y+28 \). \( 2(y+\square)(y+\square) \)

Ask by Dickson Wang. in the United States
Jan 24,2025

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Answer

\( y^{2} + 11y + 28 = (y + 4)(y + 7) \)

Solution

To factor the quadratic expression \( y^{2} + 11y + 28 \), we look for two numbers that multiply to **28** (the constant term) and add up to **11** (the coefficient of the middle term). 1. **Identify the numbers:** - The numbers **4** and **7** satisfy these conditions because: - \( 4 \times 7 = 28 \) - \( 4 + 7 = 11 \) 2. **Write the factored form:** - Using these numbers, the factored form of the quadratic is: \[ (y + 4)(y + 7) \] **Note:** The expression does not require a leading coefficient of 2. Therefore, the correct factored form is: \[ (y + 4)(y + 7) \]

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Bonus Knowledge

To factor the quadratic \( y^{2}+11 y+28 \), we look for two numbers that multiply to \( 28 \) and add up to \( 11 \). Those numbers are \( 7 \) and \( 4 \). Thus, the factored form is \( 2(y+7)(y+4) \). So, filling in the blanks, we get: \( 2(y+\mathbf{7})(y+\mathbf{4}) \).

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