Question
Razonar ** 6. Escribe el número que completa cada igualdad. \( \begin{array}{ll}\text { a. } 56+38=47 \times- & \text { c. } 72 \times \ldots=1344 \times 3 \\ \text { b. } 165 \div 3=72-\_ & \text {d. } 406-307=-1\end{array} \)
Ask by Wyatt Perkins.
Mar 21,2025 20:51
UpStudy AI Solution
Tutor-Verified Answer
Answer
a. 2
b. 17
c. 56
d. 407
Solution
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The Deep Dive
Para completar las igualdades, simplemente hay que aplicar operaciones básicas y resolver cada expresión:
a. Para \(56 + 38 = 47 \times -\), primero sumamos 56 y 38, que es 94. Entonces planteamos \(47x = 94\) y al despejar \(x\), obtenemos \(x = \frac{94}{47} = 2\). Por lo tanto, la respuesta es 2.
b. En \(165 \div 3 = 72 - \_\), primero realizamos la división \(165 \div 3 = 55\). Ahora, planteamos \(72 - x = 55\) y al despejar \(x\), encontramos que \(x = 72 - 55 = 17\). Así que la respuesta es 17.
c. En \(72 \times \ldots = 1344 \times 3\), primero calculamos \(1344 \times 3 = 4032\). Luego, planteamos \(72x = 4032\) y al despejar \(x\), tenemos \(x = \frac{4032}{72} = 56\). La respuesta es 56.
d. Para \(406 - 307 = -1\), al restar no coincide la operación, pero si corregimos a \(406 - 307\) se obtiene 99, por lo cual esto claramente lo convierte en una afirmación incorrecta ya que la igualdad no está balanceada.
Aquí están todas las respuestas:
a. 2
b. 17
c. 56
d. Inconsistente.
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