Question
upstudy study bank question image url

Sketch on the same set of axes the graphs of \( f(x)=-2 x^{2}-4 x+6 \) and \( g(x)=-2 \cdot 2^{x} \) Clearly indicate all intercepts with the axes, turning point(s) and asymptote(s).

Ask by Harper Griffin. in South Africa
Jan 19,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

To sketch the graphs of \( f(x) = -2x^{2} -4x +6 \) and \( g(x) = -2 \cdot 2^{x} \) on the same axes: 1. **Function \( f(x) \):** - **Y-Intercept:** (0, 6) - **X-Intercepts:** (-3, 0) and (1, 0) - **Vertex (Turning Point):** (-1, 8) - **Direction:** Opens downward 2. **Function \( g(x) \):** - **Y-Intercept:** (0, -2) - **No X-Intercept** - **Horizontal Asymptote:** \( y = 0 \) - **Behavior:** Decreases as \( x \) increases, approaching \( y = 0 \) as \( x \) decreases **Key Points to Plot:** - For \( f(x) \): Plot the vertex at (-1,8), intercepts at (-3,0) and (1,0), and the y-intercept at (0,6). - For \( g(x) \): Plot the y-intercept at (0,-2) and additional points like (-2, -0.5), (-1, -1), (1, -4), etc. **Intersection Points:** Solve \( -2x^{2} -4x +6 = -2 \cdot 2^{x} \) to find where the graphs intersect. This may require numerical methods for exact solutions. **Asymptotes and Behavior:** - \( f(x) \) is a downward-opening parabola with a maximum point at the vertex. - \( g(x) \) is an exponential decay function approaching the horizontal asymptote \( y = 0 \) as \( x \) increases. Use graphing tools for a precise visualization of these features.

Solution

Sign in to Unlock Answers for Free!

A Learning Platform Trusted by Millions of Real Students and Teachers.

star-icon Unlock

Reviewed and approved by the UpStudy tutoring team

Extra Insights

To sketch the graphs of \( f(x) = -2x^2 - 4x + 6 \) and \( g(x) = -2 \cdot 2^x \), start by determining their key characteristics. For \( f(x) \), it's a downward-opening parabola. To find the intercepts, set \( x = 0 \) to calculate the y-intercept, giving \( f(0) = 6 \). For the x-intercepts, we can set \( f(x) = 0 \) and solve the quadratic using the quadratic formula, yielding two roots. The vertex (turning point) can be found using \( x = -\frac{b}{2a} \), where \( a = -2 \) and \( b = -4 \), leading to the vertex at \( (-1, 8) \). For \( g(x) \), observe that it is an exponential decay function. The y-intercept occurs at \( x = 0 \), giving \( g(0) = -2 \). As \( x \) approaches infinity, \( g(x) \) approaches \( 0 \) (asymptote at \( y = 0 \)). When both plots are sketched, \( f(x) \) will approximately intersect the y-axis at 6 and have the vertex at (-1, 8), while \( g(x) \) starts at (-2) and drops off toward its horizontal asymptote. Now, grab your favorite colored pencils, and let's bring these graphs to life on the same set of axes! Remember to clearly mark the key points and features for clarity.

Related Questions

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy