Sketch on the same set of axes the graphs of \( f(x)=-2 x^{2}-4 x+6 \) and \( g(x)=-2 \cdot 2^{x} \) Clearly indicate all intercepts with the axes, turning point(s) and asymptote(s).
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To sketch the graphs of \( f(x) = -2x^2 - 4x + 6 \) and \( g(x) = -2 \cdot 2^x \), start by determining their key characteristics. For \( f(x) \), it's a downward-opening parabola. To find the intercepts, set \( x = 0 \) to calculate the y-intercept, giving \( f(0) = 6 \). For the x-intercepts, we can set \( f(x) = 0 \) and solve the quadratic using the quadratic formula, yielding two roots. The vertex (turning point) can be found using \( x = -\frac{b}{2a} \), where \( a = -2 \) and \( b = -4 \), leading to the vertex at \( (-1, 8) \). For \( g(x) \), observe that it is an exponential decay function. The y-intercept occurs at \( x = 0 \), giving \( g(0) = -2 \). As \( x \) approaches infinity, \( g(x) \) approaches \( 0 \) (asymptote at \( y = 0 \)). When both plots are sketched, \( f(x) \) will approximately intersect the y-axis at 6 and have the vertex at (-1, 8), while \( g(x) \) starts at (-2) and drops off toward its horizontal asymptote. Now, grab your favorite colored pencils, and let's bring these graphs to life on the same set of axes! Remember to clearly mark the key points and features for clarity.