Question
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\( \operatorname { ar } : ( 2 x + 3 y - 4 ) ( - 3 x + y + 2 ) \)

Ask by Mcfarlane Wade. in the United States
Jan 23,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

El resultado de la expansión es \(-6x^2 + 3y^2 - 7xy + 16x + 2y - 8\).

Solution

Para expandir el producto de los polinomios \((2x + 3y - 4)(-3x + y + 2)\), seguimos estos pasos: \[ \begin{align*} (2x + 3y - 4)(-3x + y + 2) &= 2x \cdot (-3x) + 2x \cdot y + 2x \cdot 2 \\ &\quad + 3y \cdot (-3x) + 3y \cdot y + 3y \cdot 2 \\ &\quad + (-4) \cdot (-3x) + (-4) \cdot y + (-4) \cdot 2 \\ &= -6x^2 + 2xy + 4x \\ &\quad -9xy + 3y^2 + 6y \\ &\quad + 12x - 4y - 8 \\ &= -6x^2 + 3y^2 - 7xy + 16x + 2y - 8 \end{align*} \] **Resultado final:** \[ -6x^2 + 3y^2 - 7xy + 16x + 2y - 8 \]

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Bonus Knowledge

To find the expression for \( \operatorname{ar} = (2x + 3y - 4)(-3x + y + 2) \), you can use the distributive property (also known as the FOIL method for binomials) to expand the expression. Start by multiplying each term in the first polynomial by each term in the second polynomial: \[ = 2x \cdot (-3x) + 2x \cdot y + 2x \cdot 2 + 3y \cdot (-3x) + 3y \cdot y + 3y \cdot 2 - 4 \cdot (-3x) - 4 \cdot y - 4 \cdot 2 \] Now, calculate each product: \[ = -6x^2 + 2xy + 4x - 9xy + 3y^2 + 6 - 12x - 4y - 8 \] Next, combine like terms: \[ = -6x^2 + (2xy - 9xy) + (4x - 12x) + 3y^2 + (-4y) + (6 - 8) \] This simplifies to: \[ = -6x^2 - 7xy - 8x + 3y^2 - 2 \] So the final expanded form of \( \operatorname{ar} \) is: \[ -6x^2 - 7xy - 8x + 3y^2 - 2 \]

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