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(2) \( \int \frac{10}{\sqrt[3]{3-5 x}} \mathrm{~d} x \);

Ask by Fowler Allan. in China
Jan 23,2025

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Answer

The integral of \( \frac{10}{\sqrt[3]{3-5x}} \) with respect to \( x \) is \( -3\sqrt[3]{(3-5x)^{2}} + C \).

Solution

Calculate the integral \( \int \frac{10}{\sqrt[3]{3-5x}} dx \). Evaluate the integral by following steps: - step0: Evaluate using substitution: \(\int \frac{10}{\sqrt[3]{3-5x}} dx\) - step1: Evaluate the power: \(\int \frac{10}{\left(3-5x\right)^{\frac{1}{3}}} dx\) - step2: Rewrite the expression: \(\int 10\times \frac{1}{\left(3-5x\right)^{\frac{1}{3}}} dx\) - step3: Use properties of integrals: \(10\times \int \frac{1}{\left(3-5x\right)^{\frac{1}{3}}} dx\) - step4: Use the substitution \(dx=-\frac{1}{5} dt\) to transform the integral\(:\) \(10\times \int \frac{1}{\left(3-5x\right)^{\frac{1}{3}}}\times \left(-\frac{1}{5}\right) dt\) - step5: Simplify: \(10\times \int -\frac{1}{5\left(3-5x\right)^{\frac{1}{3}}} dt\) - step6: Use the substitution \(t=3-5x\) to transform the integral\(:\) \(10\times \int \frac{-1}{5t^{\frac{1}{3}}} dt\) - step7: Rewrite the fraction: \(10\times \int -\frac{1}{5t^{\frac{1}{3}}} dt\) - step8: Rewrite the expression: \(10\times \int -\frac{1}{5}\times \frac{1}{t^{\frac{1}{3}}} dt\) - step9: Use properties of integrals: \(10\left(-\frac{1}{5}\right)\times \int \frac{1}{t^{\frac{1}{3}}} dt\) - step10: Multiply the numbers: \(-2\times \int \frac{1}{t^{\frac{1}{3}}} dt\) - step11: Evaluate the integral: \(-2\times \frac{t^{-\frac{1}{3}+1}}{-\frac{1}{3}+1}\) - step12: Simplify: \(-2\times \frac{3}{2}t^{\frac{2}{3}}\) - step13: Multiply the numbers: \(-3t^{\frac{2}{3}}\) - step14: Substitute back: \(-3\left(3-5x\right)^{\frac{2}{3}}\) - step15: Simplify: \(-3\sqrt[3]{\left(3-5x\right)^{2}}\) - step16: Add the constant of integral C: \(-3\sqrt[3]{\left(3-5x\right)^{2}} + C, C \in \mathbb{R}\) The integral of \( \frac{10}{\sqrt[3]{3-5x}} \) with respect to \( x \) is \( -3\sqrt[3]{(3-5x)^{2}} + C \), where \( C \) is an arbitrary constant.

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Extra Insights

To tackle the integral \( \int \frac{10}{\sqrt[3]{3-5 x}} \mathrm{~d} x \), you can use substitution to simplify it. Set \( u = 3 - 5x \), then \( du = -5 \, dx \) or \( dx = -\frac{1}{5} \, du \). The integral becomes \( -\frac{10}{5} \int u^{-\frac{1}{3}} \, du = -2 \int u^{-\frac{1}{3}} \, du \). Now, integrate \( u^{-\frac{1}{3}} \) to get \( -2 \cdot \frac{u^{\frac{2}{3}}}{\frac{2}{3}} + C = -3u^{\frac{2}{3}} + C \). Finally, substitute back to get \( -3(3 - 5x)^{\frac{2}{3}} + C \). Want to know how this applies in real life? Consider fields like physics or biology, where integrals can model growth rates or changes in resource availability. Understanding these concepts can help to create more accurate models and make better predictions regarding system behavior. If you're diving into integrals and exponentials, watch out for the chain rule! A common mistake is forgetting to adjust for the derivative of your substituted variable, which can lead to incorrect results. Always pay attention to the transformation of variables; it can save you a lot of hassle!

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