Porording to a study done by Nick Wilson of Otago University Wellington, the probability a randomly selected individual will not cover his or her mouth when sneezing is 0.267 . Suppos they sneeze. Complete parts (a) through (c). (a) Using the binomial distribution, what is the probability that among 16 randomly observed individuals, exactly 5 do not cover their mouth when sneezing? The probability is 0.1945 . (Round to four decimal places as needed.) (b) Using the binomial distribution, what is the probability that among 16 randomly observed individuals, fewer than 4 do not cover their mouth when sneezing? The probability is 0.6925 . (Round to four decimal places as needed.)

A six-sided die is rolled. Let A be the event "getting an odd prime number". (1) Write down the set \( \mathrm{A}, \mathrm{n}(\mathrm{A}) \) and \( \mathrm{P}(\mathrm{A}) \). (2) Draw a Venn diagram showing the actual outcomes. (3) Draw a Venn diagram showing the number of outcomes. (4) Draw a Venn diagram showing the probabilities.

9.1 Given: \( P(A)=0,45 ; P(B)=y \) and \( P(A \) or \( B)=0,74 \). Determine the value(s) of \( y \) : 9.1.1 If \( A \) and \( B \) are mutually exclusive events. 9.1.2 If \( A \) and \( B \) are independent events.

The probability that it will be suminy tomorrow is \( \frac{2}{9} \), If it is sunny, the probability tha Siya plays rugby is \( \frac{8}{15} \). If it is not sumy, the probability that Stya plays rugby is \( \frac{4}{15} \) 9.2.1 Represent the above information on the tree diagram and indicate all the possible outcomes.

En una bolsa hay cuatro tarjetas, con los números \( 1,2,3 \) y 4 respectivamente. Si se sacan dos tarjetas de la bolsa, una tras otra y con reposición, ¿cuál es la probabilidad de que la suma de los números obtenidos sea 7 ? A. \( \frac{1}{4} \) B. \( \frac{7}{16} \) C. \( \frac{1}{16} \)

The probability that it will be sunny tomorrow is \( \frac{2}{9} \). If it is sunny, the probability that Siya plays rugby is \( \frac{8}{15} \). If it is not sunny, the probability that Siya plays rugby is \( \frac{4}{15} \) 9.2.1 Represent the above information on the tree diagram and indicate all the possible outcomes.