Topic
Q:
7) En el gráfico mostrado, determina el módulo de
la fuerza eléctrica total sobre la carga \( q_{0^{*}} \)
\( \mathrm{q}_{1}=2.10^{-4} \mathrm{C} \)
\( \begin{array}{lll} & \mathrm{q}_{2}=-6.10^{-4} \mathrm{C} \quad \mathrm{q}_{0}=4.10^{-5} \mathrm{C} \\ \text { a) } 200 \mathrm{~N} & \text { b) } 22 \mathrm{~N} & \text { c) } 150 \mathrm{~N} \\ \text { d) } 500 \mathrm{~N} & \text { e) } 300 \mathrm{~N} & \end{array} \)
Q:
All changes saved
ball is thrown up in the air. At the top of its flight, it has a potential energy of 100 J and a
ip in the air and then comes back down? Select all that apply.
When it reaches the ground, it has a kinetic energy of 150 J .
As the ball falls, kinetic energy changes to potential energy.
Halfway down, it has a potential energy of 50 J and a kinetic energy of 50 J .
Q:
Ejercicio 2
Un avión vuela en un círculo horizontal con una velocidad constante de \( 300 \mathrm{~km} / \mathrm{h} \). Si el radio de la
curva es de 2 km , calcule:
a) El período de revolución del avión.
b) La aceleración centrípeta del avión.
Recuerda que para resolver estos ejercicios debes aplicar las siguientes fórmulas:
- Aceleración centrípeta (ac): ac \( =\mathrm{v}^{\wedge} 2 / \mathrm{r} \)
- Fuerza centrípeta (Fc): \( \mathrm{Fc}=\mathrm{m} \mathrm{v}^{\wedge} 2 / \mathrm{r} \)
- Período de revolución \( (\mathrm{T}): \mathrm{T}=2 \pi \mathrm{r} / \mathrm{v} \)
Q:
Determina la intensidad de la corriente eléctric
que circula por un conductor, si en un minut
pasó una carga de 600 C .
\( \begin{array}{lll}\text { a) } 600 \mathrm{~A} & \text { b) } 20 \mathrm{~A} & \text { c) } 5 \mathrm{~A} \\ \text { d) } 10 \mathrm{~A} & \text { e) } 8 \mathrm{~A} & \end{array} \)
Q:
A 40000 kg business jet takes off when the thrust
for each of its two engines is 20000 N .
Find its acceleration.
Express your answer with the appropriate units.
\( a= \) Value Units
Q:
Part A
A mass of 1 kg is accelerated \( 1 \mathrm{~m} / \mathrm{s}^{2} \) by a force of
1 N .
Select the correct equations that show that the acceleration would be the same for afforce
of 2 N acting on a 2 kg mass.
\[ \begin{array}{l}\text { a } \\ a=m / F=(2 \mathrm{~kg}) /(2 \mathrm{~N})=1 \mathrm{~m} / \mathrm{s}^{2} \\ a=F^{2} / m^{2}=(2 \mathrm{~N})^{2} /(2 \mathrm{~kg})^{2}=1 \mathrm{~m} / \mathrm{s}^{2} \\ a=m^{2} / F^{2}=(2 \mathrm{~kg})^{2} /(2 \mathrm{~N})^{2}=1 \mathrm{~m} / \mathrm{s}^{2} \\ a=F / m=(2 \mathrm{~N}) /(2 \mathrm{~kg})=1 \mathrm{~m} / \mathrm{s}^{2}\end{array} \]
Q:
A simple rearrangement of Newton's second law
reads \( F_{\text {net }}=m a \). Part A
What net force exerted on a 12-kg package is needed to produce an acceleration o, \( 7.0 \mathrm{~m} / \mathrm{s}^{2} \) ?
Q:
A 43-kg block of cement is pulled sideways with a
net force of 400 N .
What is its acceleration?
Express your answer with the appropriate units.
\( a= \) Value
Q:
Acceleration: \( a=\frac{F_{\text {net }}}{m} \)
Calculate the acceleration of a 1700 - kg , single-engine airplane as it begins its takeoff with
an engine thrust of 700 N . ( FYI: The unit \( \mathrm{N} / \mathrm{kg} \) is equivalent to \( \mathrm{m} / \mathrm{s}^{2} \).)
Express your answer in meters per second squared.
Q:
Put the following in order from the least kinetic energy to the most kinetic energy.
\( \uparrow \downarrow \) An object has a mass of 5 kg and a speed of \( 10 \frac{\mathrm{~m}}{\mathrm{~s}} \).
\( \uparrow \downarrow \) An object has a mass of 20 kg and a velocity of \( 4 \frac{\mathrm{~m}}{\mathrm{~s}} \).
\( \uparrow \downarrow \) An object has a mass of 15 kg and a velocity of \( 6 \frac{\mathrm{~m}}{\mathrm{~s}} \).
\( \uparrow \downarrow \) An object has a mass of 10 kg and a speed of \( 5 \frac{\mathrm{~m}}{\mathrm{~s}} \).
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