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Home Question Bank Chemistry Archive 2024 November 10

Chemistry Questions from Nov 10,2024

Browse the Chemistry Q&A Archive for Nov 10,2024, featuring a collection of homework questions and answers from this day. Find detailed solutions to enhance your understanding.

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For a second-order reaction with the rate law: rate \( =k[A] \wedge 2 \), the half-life is: (A) Directly proportional to the initial concentration (B) Inversely proportional to the initial concentration (C) Independent of the initial concentration (D) Proportional to the square of the initial concentration If the half-life of a reaction is found to be constant regardless of the initial concentration, the reaction is likely' (A) zero-order (B) First-order (C) second-order (D) Third-order For a reaction with the rate law: rate \( =k[A][B]^{\wedge} 2 \), the reaction is: (A) First-order in \( A \) and first-order in \( B \) B) First-order in \( A \) and second-order in B C. Second-order in \( A \) and first-order in B (D) Second-order in \( A \) and second-order in B - In a first-order reaction, if the concentration of the reactant decreases from 0.8 M to 0.4 M in 10 minutes, the half fife of the reaction is: 5 min (A) 10 min (C) 15 min (D) 20 min For a zero-order reaction, the plot of concentration vs. time is a: (A) Straight line with a positive slope (B) Straight line with a negative slope (C) Curve with a positive slope (D) Curve with a negative slope Un compuesto dio la siguiente composición porcentual en masa: \( 26,57 \% \) de \( \mathrm{K}, 35,36 \% \) de \( \mathrm{Cry} 38,07 \% \) de O. Determinar la fórmula empírica del compuesto. Calcule la composición centesimal de los siguientes compuestos: \( \begin{array}{lll}\text { a) } \mathrm{Na}_{2} \mathrm{SO}_{4} .5 \mathrm{H}_{2} \mathrm{O} & \text { d) } \mathrm{Pb}\left(\mathrm{C}_{2} \mathrm{H}_{5}\right) & \text { g) } \mathrm{Na}_{2} \mathrm{SO}_{4}\end{array} \) Un compuesto orgánico sintetizado arrojó los siguientes porcentajes \( 27,06 \% \) de \( \mathrm{C} ; 3,75 \% \) de \( \mathrm{H} ; 21,05 \% \) de Ny el resto de oxígeno, si la masa molar del compuesto es \( 266 \mathrm{~g} / \mathrm{mol} \). Halle la fórmula molecular. La progesterona es un componente común de la píldora anticonceptiva. Si su fórmula empírica es \( \mathrm{C}_{21} \mathrm{H}_{30} \mathrm{O}_{2} \), ¿cuál es su composición porcentual? Which one of the following electron configuration notations represent an ion of a halogen? \( \begin{array}{l}\text { A } 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} \\ \text { B } 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} \\ \text { C } \quad s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5} \\ \text { D } 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{1}\end{array} \) El peso molecular de la sacarina es de \( 183 \mathrm{~g} / \mathrm{mol} \) y el compuesto contiene \( 45,9 \% \mathrm{de} \mathrm{C}, 2,75 \% \) de H , \( 26,20 \% \) de \( \mathrm{O}, 17,5 \% \) de S, y 7,655 de N . ¿Cuál es la fórmula molecular de la sacarina? de compuesto orgánico sintetizado arrojó los siguientes porcentajes \( 27,06 \% \) de \( \mathrm{C} ; 3,75 \% \) de \( \mathrm{H} ; 21,05 \% \) La prosto de oxígeno, si la masa molar del compuesto es \( 266 \mathrm{~g} / \mathrm{mol} \). Halle la fórmula molecular. \( \mathrm{C}_{21} \mathrm{H}_{30} \mathrm{O}_{2} \), ¿cuál es su composición porcentual? This balanced chemical equation represents the reaction between methane \( \left(\mathrm{CH}_{4}\right) \) and steam \( \left(\mathrm{H}_{2} \mathrm{O}\right) \) : \[ \mathrm{CH}_{4}(\mathrm{~g})+\mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \rightarrow \mathrm{CO}(\mathrm{g})+3 \mathrm{H}_{2}(\mathrm{~g}) \] The volume of methane (in \( \left.\mathrm{m}^{3}\right) \) needed to form \( 150 \mathrm{~m}^{3} \) of hydrogen at the same temperature and pressure is \( \ldots \) A 25. B 50. C 75. D 150.
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