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Home Question Bank Math Archive 2024 December 08

Math Questions from Dec 08,2024

Browse the Math Q&A Archive for Dec 08,2024, featuring a collection of homework questions and answers from this day. Find detailed solutions to enhance your understanding.

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Perform the indicated operation. Simplify if possible. \( \frac{x^{2}}{x-9}-\frac{20 x-99}{x-9} \) The difference is \( \square \). ability Basic Concepts Two fair coins are tossed (say a dime and a quarter). The two possible outcomes for a single coin are heads, h, and tails, t Give each of the following. (a) the sample space (b) the probability of heads on the dime (c) the probability of heads on the quarter (d) the probability of getting both heads (e) the probability of getting the same outcome on both coins (a) The sample space is \( \{ \) ?. (Use a comma to separate answers as needed.) Use elimination to solve the system of equations \( \begin{array}{l}3 x+5 y=11 \\ 5 x-5 y=5\end{array} \) 4. Use the space to describe how to find "h" for each type of prism: TRIANGULAR: RECTANGULAR: 1. Solve the following equation or state that the equation has no solutions Remembering to ched for evtremeots solutions. \( 2-\frac{2 x-2}{2 x}=\frac{2}{2 x+4 x} \) \( \frac{x+6}{x^{2}-2 x-8}+\frac{x+9}{x^{2}-5 x-14}=\square \) (Simplify your answer.) II. Graph and construct a sign chart for the following rational inequalities. \( \frac{x^{2}+4 x+3}{x-1}>0 \) Solution: \( \frac{y^{2}-2 y-15}{y^{2}-6 y+9} \div \frac{y-5}{y-3}=\square \) (Simplify your answer.) A four-sided figure is resized to create a scaled copy. The proportional relationship between any given side length in the original figure, \( f \), and the corresponding side length in the scaled copy, \( s \), can be represented by the equation \( s=\frac{1}{6} f \). What is the constant of proportionality from side lengths in the original figure to side lengths in the scaled copy? 11. [-/4 Points] DETAILS MY NOTES HARMATHAP12 4.2.020. Solve the following linear programming problem. Restrict \( x \geq 0 \) and \( y \geq 0 \). Minimize \( g=50 x+80 y \) subject to the following. \[ \begin{array}{r}11 x+15 y \geq 255 \\ x+3 y \geq 33\end{array} \] \( (x, y)=\left(\begin{array}{l}15,6\end{array}\right. \) \( g=\square \)
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