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Home Question Bank Math Archive 2024 November 09

Math Questions from Nov 09,2024

Browse the Math Q&A Archive for Nov 09,2024, featuring a collection of homework questions and answers from this day. Find detailed solutions to enhance your understanding.

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The term \( 15 x^{2} y^{4} \) is a term in which binomial expansion? \( \frac{(5 x+3 y)^{6}}{(x+y)^{4}} \) \( \frac{(x+y)^{6}}{(5 x+3 y)^{4}} \) Question algebraically. Answer Attempt 1 out of 2 (1) Add a zero \( \odot \) No zeros \( x=x^{3}+7 x^{2}+2 x-40 \) and \( x+4 \) is a factor of \( f(x) \), then find all of the zeros of \( f(x) \) On a placé 2 jetons jaunes, 3 rouges et 2 verts dans une boîte. On tire un premier ieton. Puis, sans remettre le premier jeton dans la boîte, on en tire un deuxième. Représenter les résultats de cette expérience aléatoire par un arbre de probabilités. El resultado de solucionar el producto dado es: \[ (\boldsymbol{x}-\mathbf{1 0})(\boldsymbol{x}+\mathbf{1 0}) \] Write each expression in the form \( 2^{k x} \) or \( 3^{k x} \) for a suitable constant \( k \). \( \begin{array}{lll}\text { (a) } 16^{x} & \text { (b) }(\sqrt{3})^{x} & \text { (c) }\left(\frac{1}{27}\right)^{x} \\ \text { (a) } 16^{x}=\square & \end{array} \) Question 2 Use the Binomial Theorem to expand \( \left(x+\frac{1}{2}\right)^{3} \) \( \frac{x^{3}}{8}+\frac{3}{4} x^{2}+\frac{3}{2} x+\frac{1}{2} \) \( \frac{x^{3}+3 x^{2}+3 x+1}{x^{3}+\frac{3}{2} x^{2}+\frac{3}{4} x+\frac{1}{8}} \) \( x^{3}+\frac{1}{2} x^{2}+\frac{1}{4} x+\frac{1}{8} \) El resultado de solucionar el producto dado es: \[ \left(7 a^{3} b^{4}-9 x^{6} y\right)\left(9 x^{6} y+7 a^{3} b^{4}\right) \] If \( f(x)=x^{3}+11 x^{2}+20 x-32 \) and \( f(-4)=0 \), then find all of the zeros of \( f(x) \) algebraically. Answer Attempt 1 out of 2 (๑) Adda azero \( \odot \) Nozeros \( x=\square \) Desarrolle el siguiente producto notable \[ (x-11)(x-8) \] 39) \( \sqrt{48 x^{3}} \)
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