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Home Question Bank Math Algebra Archive 2024 November 03

Algebra Questions from Nov 03,2024

Browse the Algebra Q&A Archive for Nov 03,2024, featuring a collection of homework questions and answers from this day. Find detailed solutions to enhance your understanding.

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Multiply the fractions. Simplify if possible. \[ \frac{8 x+8 y}{5} \cdot \frac{10}{x+y} \] Solve the absolute value equation. \( |6 x+6|=11 \) Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The solution set is \{ \}. (Type an integer or a simplified fraction. Use a comma to separate answers as needed.) B. The solution is the empty set. Multiply. \( \frac{(x+4)}{(x-4)(x-5)} \cdot \frac{(x-5)(x+5)}{(x-1)(x+4)} \) 2) Plantear,resolver y escribir la respuesta de los siguientes problemas. a) La tercera parte de la edad de Julio es igual al producto entre la raíz cuadrada de veinticinco, y dos. ¿Cuál es la edad de Julio? b) La mitad de la edad de Pablo es igual al producto entre tres y el cubo de dos. ¿Cuál es la edad de Pablo? c) La cuarta parte de la edad de Carmen es igual a la diferencia entre veintidós y la raíz cúbica de 64. ¿Cuál es la edad de Carmen? Determine whether the ordered pairs given are solutions of the linear inequality in two variables. \( y-x>4 ;(0,-4),(-2,2) \) Is the ordered pair \( (0,-4) \) a solution to the inequality? No Yes Is the ordered pair \( (-2,2) \) a solution to the inequality? Yes Si una función lineal tiene una tasa de cambio de -4, escribe una posible forma de su ecuación. Question 2 (1 mark) Solve this matrix cquation for \( X \) \( \left[\begin{array}{cc}2 & 2 \\ 2 & -5\end{array}\right] X=\left[\begin{array}{cc}8 & 6 \\ -13 & -1\end{array}\right] \) A. \( \left[\begin{array}{cc}-1 & -2 \\ -3 & -1\end{array}\right] \) B. \( \left[\begin{array}{cc}1 & 2 \\ 3 & 1\end{array}\right] \) C. \( \frac{1}{-14}\left[\begin{array}{cc}-14 & -28 \\ -42 & -14\end{array}\right] \) D. \( \frac{1}{-14}\left[\begin{array}{cc}-14 & -28 \\ -42 & -14\end{array}\right] \) E. \( \frac{1}{-14}\left[\begin{array}{cc}-52 & -4 \\ 68 & 24\end{array}\right] \) . Given that \( 25^{x}=1 \), find \( x \) Divide the fractions. Reduce to simplest form. \[ \frac{19 r^{2}}{8 a^{2}} \div \frac{95 r^{2}}{2 a} \] c) \( \left\{\begin{array}{c}a x+b y=2 a b \\ x+y=a+b\end{array}\right. \)
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