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Home Question Bank Math Algebra Archive 2024 November 05

Algebra Questions from Nov 05,2024

Browse the Algebra Q&A Archive for Nov 05,2024, featuring a collection of homework questions and answers from this day. Find detailed solutions to enhance your understanding.

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Elija la opción que se obtiene al resolver: \( \frac{x^{2}+7 x+12}{6 x^{2}+5 x-6} \leq 0 \) \( \square \) a. \( -4 \leq x \leq-3 \vee-\frac{3}{2}<x<\frac{2}{3} \) \( \square \) b. \( \quad-\frac{3}{2}<x<\frac{2}{3} \vee 3 \leq x \leq 4 \) \( \square \) c. \( \quad-4<x<-3 \vee-\frac{3}{2} \leq x \leq \frac{2}{3} \) \( \square \) d. \( \quad-\frac{3}{2} \leq x \leq \frac{2}{3} \vee 3<x<4 \) ¿Cuál es la solución del siguiente ejercicio \( \sqrt{x+3}+\sqrt{x+4} \geq 0 \) ? \( \square \) a. \( \quad[-4 ; \infty) \) \( \square \) b. \( \quad \mathbb{R} \) \( \square \) c. \( \quad[-4 ;-3] \) \( \square \) d. \( [-3 ; \infty) \) Factor the polynomial: \( x^{3} - 6x^{2} + 11x - 6 \) Factorizar \( 1-9 a^{2} b^{4} c^{6} d^{8} \) Resuelva la siguiente inecuación \( \frac{1}{9}<\frac{1}{x+2} \leq \frac{1}{2} \) \( \square \) a. \( ] 0 ; 7] \) \( \square \) b. \( ]-\infty ; 0] \cup] 7 ; \infty[ \) \( \square \) c. \( [0 ; 7[ \) \( \square \) d. \( ]-\infty ; 0[\cup[7 ; \infty[ \) a) \( -4 x^{2}-8=140 \) F) \( 3+5 \cdot 2^{3 x}=7 \) \( f ( x ) = a x ^ { 2 } + b x + c , a \neq 0 \) Olivia compró libros a uS\$4 cada uno y obtuvo un descuento de uS\$5 en la compra total. Ella gastó us\$7ı con el descuento incluido. ¿Cuántos libros compró? Hallar el intervalo solución de \( \frac{x+1}{x-6}<7 \). \( \square \) a. \( ] 6 ; \frac{43}{6}[ \) \( \square \) b. \( ]-\infty ; 6[\mathrm{u}] \frac{43}{6} ; \infty[ \) \( \square \) c. \( \mid-6 ; \frac{43}{6}[ \) \( \square \) d. \( ]-\infty ;-6[\mathrm{U}] \frac{43}{6} ; \infty[ \)
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