Algebra Questions from Nov 06,2024

Browse the Algebra Q&A Archive for Nov 06,2024, featuring a collection of homework questions and answers from this day. Find detailed solutions to enhance your understanding.

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Determine the number and type of solutions of the quadratic equation. \( -4 x^{2}-4 x-1=0 \) two imaginary solutions two real solutions one real solution one imaginary solution 4. Gegeben sind die Funktionen \( f_{a} \) mit \( f_{a}(x)=x^{2}+a x+a, a \in \mathbb{R} \). a) Zeichnen Sie die Graphen für \( a=-1, a=0 \) und \( a=2 \) mit einem Rechner. b) Berechnen Sie den Wert von \( a \), für den der Graph von \( f_{a} \) seinen Tiefpunkt an der Stelle \( x=2,5 \) hat. Determine the number and type of solutions of the quadratic equation. \( x^{2}+10 x-25=0 \) one real solution one imaginary solution two imaginary solutions two real solutions (2) \( \left\{\begin{array}{l}6 x+5 y=23 \\ -4 y+y=-11\end{array}\right. \) I. \( \quad \) "Solve for \( \mathbf{x}^{\prime \prime} \) Write your solution. 1. \( 16^{2 x-3}=4^{x+2} \) Solve using the Quadratic Formula. \( \begin{array}{l}6 x^{2}+7 x-5=0 \\ x=\frac{-7 \pm i \sqrt{71}}{12} \\ x=-\frac{1}{2} \text { and } x=\frac{5}{3} \\ x=\frac{-7 \pm i \sqrt{71}}{2} \\ x=\frac{1}{2} \text { and } x=-\frac{5}{3}\end{array} \) 01. Al repartir una cantidad "A" en forma DP a los numeros \( 1 ; 2 ; 3 \) y 5 , las dos cantidades mayores repartidas suman 160 . Determinar el valor de "A". \( \begin{array}{lll}\text { A) } 20 & \text { B) } 40 & \text { C) } 60 \\ \text { D) } 180 & \text { E) } 220 & \end{array} \) 1AREA \( m=\frac{y_{2}-y_{1}}{x-x_{1}} \) Con esta formula \( y-y_{1}=m\left(x-x_{1}\right) \) Hallar la ecuacion de la recta que pasa por los puntos \( M\left(-\frac{3}{2}, \frac{3}{2}\right) \) y \( P\left(2, \frac{1}{3}\right) \) No hay que graficar Factorizal \( 4-(a-1)^{2} \) Solve using the Quadratic Formula. \( \begin{array}{l}3 x^{2}+4 x+5=0 \\ x=\frac{-2 \pm \sqrt{11}}{3} \\ x=\frac{-4 \pm 2 i \sqrt{11}}{2} \\ x=\frac{-4 \pm i \sqrt{11}}{6} \\ x=\frac{-2 \pm i \sqrt{11}}{3}\end{array} \)
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