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Home Question Bank Math Calculus Archive 2025 January 19

Calculus Questions from Jan 19,2025

Browse the Calculus Q&A Archive for Jan 19,2025, featuring a collection of homework questions and answers from this day. Find detailed solutions to enhance your understanding.

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The derivative of the function \( f \) is defined by \( f^{\prime}(x)=x^{2} \sin \left(x^{2}-x\right) \). If \( f(2)=3 \), what is the absolute minimum value of the function \( f \) on the closed interval \( [-2,2] \) ? You may use a calculator and round your answer to the nearest thousandth. The derivative of the function \( f \) is defined by \( f^{\prime}(x)=x^{2} \sin \left(x^{2}-x\right) \). If \( f(2)=3 \), what is the absolute minimum value of the function \( f \) on the closed interval \( [-2,2] \) ? You may use a calculator and round your answer to the nearest thousandth. The derivative of the function \( f \) is defined by \( f^{\prime}(x)=x^{2} \sin \left(x^{2}-x\right) \). If \( f(2)=3 \), what is the absolute minimum value of the function \( f \) on the closed interval \( [-2,2] \) ? You may use a calculator and round your answer to the nearest thousandth. The derivative of the function \( f \) is defined by \( f^{\prime}(x)=x^{2} \sin (3 x) \). If \( f(0)=5 \), what is the absolute maximum value of the function \( f \) on the closed interval \( [-2,2] \) ? You may use a calculator and round your answer to the nearest thousandth. The derivative of the function \( f \) is defined by \( f^{\prime}(x)=x^{2} \sin (3 x) \). If \( f(0)=5 \), what is the absolute maximum value of the function \( f \) on the closed interval \( [-2,2] \) ? You may use a calculator and round your answer to the nearest thousandth. he derivative of the function \( f \) is defined by \( f^{\prime}(x)=x^{2} \sin (3 x) \). If \( f(0)=5 \), hat is the absolute maximum value of the function \( f \) on the closed interval \( -2,2] \) ? You may use a calculator and round your answer to the nearest nousandth. The derivative of the function \( f \) is defined by \( f^{\prime}(x)=x^{2} \sin (3 x) \). If \( f(0)=5 \), what is the absolute maximum value of the function \( f \) on the closed interval \( [-2,2] \) ? You may use a calculator and round your answer to the nearest thousandth. The derivative of the function \( f \) is defined by \( f^{\prime}(x)=\left(x^{2}-5 x\right) \cos (x-3) \). What is the \( x \)-coordinate of the absolute minimum value of the function \( f \) on the closed interval \( [-2,2] \) ? You may use a calculator and round your answer to the nearest thousandth. The derivative of the function \( f \) is defined by \( f^{\prime}(x)=\left(x^{2}-5 x\right) \cos (x-3) \), What is the \( x \)-coordinate of the absolute minimum value of the function \( f \) on the closed interval \( [-2,2] \) ? You may use a calculator and round your answer to the nearest thousandth. The derivative of the function \( f \) is defined by \( f^{\prime}(x)=\left(x^{2}-5 x\right) \cos (x-3) \), What is the \( x \)-coordinate of the absolute minimum value of the function \( f \) on the closed interval \( [-2,2] \) ? You may use a calculator and round your answer to the nearest thousandth.
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