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Home Question Bank Math Pre Algebra Archive 2024 December 10

Pre-algebra Questions from Dec 10,2024

Browse the Pre-algebra Q&A Archive for Dec 10,2024, featuring a collection of homework questions and answers from this day. Find detailed solutions to enhance your understanding.

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\( \begin{array}{ll}\text { 1) } \sqrt[5]{3^{10} \cdot 2^{15}} ; & \text { 2) } \sqrt[3]{2^{3} \cdot 5^{6}} \\ \text { 3) } \sqrt[4]{3^{12}\left(\frac{1}{3}\right)^{8}} ; & \text { 4) } \sqrt[10]{4^{30} \cdot\left(\frac{1}{2}\right)^{20}}\end{array} \) Fill in the missing values to make the equations true. (a) \( \log _{5} 11-\log _{5} 8=\log _{5} \) (1] (b) \( \log _{7} \square+\log _{7} 2=\log _{7} 18 \) (c) \( 2 \log _{5} 3=\log _{5} \square \) When removing a negative coefficient in an inequality, such as \( -2 x>10 \), you must flip the inequality symbol. True False 9. \( \frac{3 \sqrt{2}-\sqrt{24}}{2 \sqrt{8}} \) expresa la fracción cono en poncentage algunas respuestas son decimales \[ \frac{1}{20}=? \] Which property or axoim is shown below \[ \begin{array}{l}5+0=5 \\ \text { additive identity } \\ \text { additive inverse } \\ \text { associative axiom } \\ \text { commuative axiom }\end{array} \] a. \( \sqrt[5]{-32} \) \( \frac{4}{12}=\frac{u}{9} \) Simplify your answer as much as possible. \( u=\square \) \( \begin{array}{lll}33 & \text { 1) } \sqrt[3]{343 \cdot 0,125} ; & \text { 2) } \sqrt[3]{512 \cdot 216} ; \\ 34 & \text { 3) } \sqrt[5]{32 \cdot 100000} \\ 34 & \left.\text { 1) } \sqrt[3]{5^{3} \cdot 7^{3}} ; \text { 2) } \sqrt[4]{11^{4} \cdot 3^{4}} ; 3\right) \sqrt[5]{(0,2)^{5} \cdot 8^{5}} \text {; 4) } \sqrt[7]{\left(\frac{1}{3}\right)^{7} \cdot 21^{7}} \\ 35 & \text { 1) } \sqrt[3]{2} \cdot \sqrt[3]{500} ; \text { 2) } \sqrt[3]{0,2} \cdot \sqrt[3]{0,04} ; 3) \sqrt[4]{324} \cdot \sqrt[4]{4} ; 4) \sqrt[5]{2} \cdot \sqrt[5]{16}\end{array} \) \begin{tabular}{l} Assinale a alternativa que apresenta o número de anagramas iniciados por vogal que \\ podem ser formados com a palavra IATE \\ 24 \\ 256 \\ 18 \\ \hline\end{tabular}
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