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Home Question Bank Math Pre Calculus Archive 2024 November 04

Pre-calculus Questions from Nov 04,2024

Browse the Pre-calculus Q&A Archive for Nov 04,2024, featuring a collection of homework questions and answers from this day. Find detailed solutions to enhance your understanding.

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Hallar el dominio y el rango de \( y=\frac{\sqrt{x+5}}{2 x-3} \) nuestra foncion \[ y=\frac{\sqrt{x-1}}{x+3} \] Hallar el domenio y elrango de \( y=\sqrt{\frac{x+5}{2 x-3}} \) Draw the graph of \( f(x)=\left(\frac{1}{5}\right)^{x+3}+2 \) 5. Determine una ecuación de una función \( y=f(x) \) de tal manera que los conjuntos dados sean el más grande que tengan como dominio a. \( [3,+\infty) \) b. \( [-5,5] \) c. \( (-\infty, 3] \cup[3,+\infty) \) d. \( (-\infty, 3) \cup(3,+\infty) \) e. \( \mathbb{R}-\{2,5\} \) 5. Determine una ecuación de una función \( y=f(x) \) de tal manera que los conjuntos dados sean el más grande que tengan como dominio a. \( [3,+\infty) \) b. \( [-5,5] \) c. \( (-\infty, 3] \cup[3,+\infty) \) d. \( (-\infty, 3) \cup(3,+\infty) \) e. \( \mathbb{R}-\{2,5\} \) The function \( f \) is defined as follows. \[ f(x)=\left\{\begin{array}{ll}-2 x+3 & \text { if } x<1 \\ 2 x-1 & \text { if } x \geq 1\end{array}\right. \] (a) Find the domain of the function. (b) Locate any intercepts. (c) Graph the function. (d) Based on the graph, find the range. 4. Um carro se movimenta em velocidade constante, de acordo com a função defi- nida por \( y=2 x+1 \), em que \( y \) representa a posição, em metro, do carro no instante \( x \), em segundo. Esboce, no plano cartesiano, o gráfico que descreve a posição do carro em função do tempo. Lembre-se de que, nesse caso, a variável \( x \) assume apenas valores reais não neqativos. 3estäm definitionsmängd till funktionen \( y=\frac{x+1}{x(x-2)} \) Usa el análisis de cada función radical para realizar su gráfica. \( \begin{array}{ll}\text { 13. } f(x)=\sqrt{3 x} & \text { 17. } f(x)=\sqrt{-2 x-4} \\ \text { 14. } f(x)=\sqrt{x+8} & \text { 18. } f(x)=\sqrt{-x-\frac{5}{2}} \\ \text { 15. } f(x)=\sqrt{-4-x} & \text { 19. } f(x)=\sqrt{\frac{x+3}{8}} \\ \text { 16. } f(x)=\sqrt{2 x-\frac{2}{3}} & \text { 20. } f(x)=\sqrt{\frac{3 x-5}{2}}\end{array} \)
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