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Home Question Bank Math Statistics Archive 2024 December 08

Statistics Questions from Dec 08,2024

Browse the Statistics Q&A Archive for Dec 08,2024, featuring a collection of homework questions and answers from this day. Find detailed solutions to enhance your understanding.

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Explain whether the Midrange measures central tendency, dispersion, or position, and why. Midrange \( =\frac{\text { minimum item }+ \text { maximum item }}{2} \) Choose the correct answer below. A. The midrange measures dispersion, because it indicates how much the data B. The midrange measures position, because it describes the relative location of a particular item within the data set. C. The midrange measures central tendency, because it is a central value representative of an entire set of numbers. Describe cómo puedes determinar si hay una correlación positiva entre dos variables utilizando un diagrama de dispersión. The board of a major credit card company requires that the mean wait time for customers when they call customer service is at most 5.00 minutes. To make sure that the mean wait time is not exceeding the requirement, an assistant manager tracks the wait times of 51 randomly selected calls. The mean wait time was calculated to be 5.42 minutes. Assuming the population standard deviation is 1.95 minutes, is there sufficient evidence to say that the mean wait time for customers is longer than 5.00 minutes with a \( 90 \% \) level of confidence? Step 2 of \( 3: \) Compute the value of the test statistic. Round your answer to two decimal places. Answer The 64 students in a classical music lecture class were polled, with the results that 35 like Wolfgang Amadeus Mozart, 34 like Ludvig von Beethoven, 30 like Franz Joseph Haydn, 12 Mozart and Beethoven, 21 like Mozart and Haydn, 12 like Beethoven and Haydn, and 7 like all three composers. Use a Venn diagram to complete parts (a) through (f). (a) now many or mese suoens uke exacuy two or mese composers, 24) student(s) (Simplify your answer.) (b) How many of these students like exactly one of these composers? (Simplify your answer.) (c) How many of these students like none of these composers? 3. student(s) (Simplify your answer.) (d) How many of these students like Mozart, but neither Beethoven nor Haydn? \( \square \) student(s) (Simplify your answer.) (e) How many of these students like Haydn and exactly one of the other two? (Simplify your answer.) (i) How many of these students like no more than two of these composers? (Simplify your answer.) The board of a major credit card company requires that the mean wait time for customers when they call customer service is at most 5.00 minutes. To make sure that the mean walt time is not exceeding the requirement, an assistant manager tracks the wait times of 51 randomly selected calls. The mean wait time was calculated to be 5.42 minutes. Assuming the population standard deviation is 1.95 minutes, is there sufficient evidence to say that the mean wait time for customers is longer than 5.00 minutes with a \( 90 \% \) level of confidence? Step 1 of 3 : State the null and alternative hypotheses for the test. Fill in the blank below. Answer A national business magazine reports that the mean age of retirement for women executives is 60.8 . A women's rights organization believes that this value does not accurately depict the current trend in retirement. To test this, the group polled a simple random sample of 80 recently retired women executives and found that they had a mean age of retirement of 59.8 . Assuming the population standard deviation is 4.1 years, is there sufficient evidence to support the organization's belief at the 0.0 I level of significance? Step 3 of 3 : Draw a conclusion and interpret the decision. Answer We fail to reject the null hypothesis and conclude that there is sufficient evidence at a 0.01 level of significance to support the belief that the mean age of retirement for women executives is not 60.8 . We reject the null hypothesis and conclude that there is insufficient evidence at a 0.01 level of significance to support the belief that the mean age of retirement for women executives is not 60.8 . We fail to reject the null hypothesis and conclude that there is insufficient evidence at a 0.01 level of significance to support the belief that the mean age of retirement for women executives is not 60.8 . d me your location (Should be done in Excel or Spreadsheets) A. Below is collection of responses to the question: "How many parking tickets have you received this semester?" \( \begin{array}{l}1,1,0,1,2,2,0,0,0,3,3,0,3,3,0,2,2,2,1,1,4,1,1,0,3,0,0,0,1,1,2,2,2 \text {, } \\ 2,1,1,1,1,4,4,4,1,1,1,1,2,2,2,2,2,2,2,2,1,1,1,1,1,3,3,0,3,3,1,1,1 \text {, } \\ 1,0,0,1,1,1,1,3,3,3,2,3,3,1,1,1,2,2,2,4,5,5,4,4,1,1,1,4,1,1,1,3,3 \text {, } \\ 5,3,3,3,2,3,3,0,0,0,0,3,3,3,3,3,3,0,2,2,2,2,1,1,1,3,1,0,0,0,1,1 \text {, } \\ 3,1,1,1,2,2,2,4,2,2,2,1,1,1,1,0,0,2,2,3,3,2,2,3,2,0,0,1,1,3,3,3,1 \text {, } \\ 1,1,1,1,2,2,2,2,1,1,1,1,0,1,1,1,3,1,1,1,2,2,2,1,1,1,2,1,1,1,3,3,5,3 \text {, } \\ 3,1,1,1,3,3,3,3,1,1,1,4,1,1,4,4,4,4,4,4,1,1,1,2,2,5,5,2,3,3,4,4,3,2 \text {, } \\ 2,2,1,5,1,2,2,1,1,1,2,2,2,2,2,1,1,0,1,1,1,3,3,3,3,3\end{array} \) Organize and arrange the data numerically. ( 5 points) In excel file, create a Frequency Distribution Table (FDT) label the first column "number of tickets" and second column "frequency". ( 20 points) Find the mode of the data set using the FDT. Highlight the mode on the table. (10 points) Find the Mean of data set. The \( n \) of the data set is equal to the sum of frequencies. Add a column to the FDT and label the third column "number of tickets X frequency". In the formula bar, type =(highlight the data under "number of tickets" * "frequency"), enter. Once done, type = Sum(highlight the data from the top to bottom)/total number of frequencies, enter. Highlight the answer. (30 Below is collection of responses to the question: "How many parking tickets have you received this semester?" \( \begin{array}{l}1,1,0,1,2,2,0,0,0,3,3,0,3,3,0,2,2,2,1,1,4,1,1,0,3,0,0,0,1,1,2,2,2 \text {, } \\ 2,1,1,1,1,4,4,4,1,1,1,1,2,2,2,2,2,2,2,2,1,1,1,1,1,3,3,0,3,3,1,1,1 \text {, } \\ 1,0,0,1,1,1,1,3,3,3,2,3,3,1,1,1,2,2,2,4,5,5,4,4,1,1,1,4,1,1,1,3,3 \text {, } \\ 5,3,3,3,2,3,3,0,0,0,0,3,3,3,3,3,3,0,2,2,2,2,1,1,1,3,1,0,0,0,1,1 \text {, } \\ 3,1,1,1,2,2,2,4,2,2,2,1,1,1,1,0,0,2,2,3,3,2,2,3,2,0,0,1,1,3,3,3,1 \text {, } \\ 1,1,1,1,2,2,2,2,1,1,1,1,0,1,1,1,3,1,1,1,2,2,2,1,1,1,2,1,1,1,3,3,5,3 \text {, } \\ 3,1,1,1,3,3,3,3,1,1,1,4,1,1,4,4,4,4,4,4,1,1,1,2,2,5,5,2,3,3,4,4,3,2 \text {, } \\ 2,2,1,5,1,2,2,1,1,1,2,2,2,2,2,1,1,0,1,1,1,3,3,3,3,3\end{array} \) The value of \( \frac{\sigma}{\sqrt{n}} \) for \( n=100 \) is Round to four decimal places.
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