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Home Question Bank Math Trigonometry Archive 2024 November 23

Trigonometry Questions from Nov 23,2024

Browse the Trigonometry Q&A Archive for Nov 23,2024, featuring a collection of homework questions and answers from this day. Find detailed solutions to enhance your understanding.

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Find the general solution of \( 2 \sin \theta^{2}-\sin \theta-1=0 \) (a) \( t=\arcsin \left(\frac{\sqrt{2}}{2}\right) \) This means that \( \square \) where \( t \) lies in the interval If the range of the function \( f: f(x)=a \cos b x, a>0, b>0 \) is \( [-2,2], f \) is a periodic function and its period \( =\frac{\pi}{2} \) , then \( : \frac{a}{b}=\ldots \ldots \ldots \ldots \) \( \begin{array}{lll}\text { a) } 1 & \text { b) } \frac{1}{2} & \text { d) } \frac{1}{4}\end{array} \) If \( \frac{2-\cos x}{5}=\mathbf{m} \), then \( \mathbf{m} \in \ldots \ldots \) \( \begin{array}{ll}\text { a) }\left[\frac{1}{5}, \frac{3}{5}\right] & \text { b) }\left[-\frac{1}{5}, \frac{3}{5}\right] \\ \text { c) }\left[-\frac{2}{5}, \frac{3}{5}\right] & \text { d) }\left[-\frac{1}{5}, \frac{2}{5}\right]\end{array} \) Question 1 (1 point) \( \begin{array}{l}\text { Given the measurement of angle } \mathrm{A}=35.4^{\circ} \text {, determine the measure of the } \\ \text { complement of angle } \mathrm{A} \text {. } \\ 144.6 \\ 56.4 \\ 125.4 \\ 54.6^{\circ}\end{array} \) Indica el signo de todas las razones trigonométricas de los siguientes ángulos expresados en grados. \( \begin{array}{llll}\text { a. } 120^{\circ} & \text { b. }-70^{\circ} & \text { c. } 256^{\circ} & \text { d. } 800^{\circ} \\ \text { e. } 315^{\circ} & \text { f. } 1200^{\circ} & \text { g. } 55^{\circ} & \text { h. }-460^{\circ}\end{array} \) TAREA DE MAT Demosthar que las siguente (1) \( \operatorname{cotg} \frac{x}{4}=\frac{\operatorname{sen} \frac{x}{2}}{1-\cos \frac{x}{2}} \) A hipotenusa de um triângulo mede 40 cm , e a razão entre os catetos é de \( \frac{3}{4} \). Calcule as medidas dos catetos. Find the component form of \( \mathbf{v} \) given its magnitude and the angle it makes with the positive \( x \)-axis. \[ \begin{array}{l}\text { magnitude } \\ \|\mathbf{v}\|=8 \quad \mathbf{v} \text { in the direction } 3 \mathbf{i}+4 \mathbf{j}\end{array} \] Find the component form of \( \mathbf{v} \) given its magnitude and the angle it makes with the positive \( x \)-axis. \[ \begin{array}{l}\text { magnitude } \\ \qquad \mathbf{v} \|=2 \sqrt{13} \\ \text { angle } \\ \theta=45^{\circ}\end{array} \]
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