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Factor completely. \( 6 y^{2}-24 y+36 \) पు

Ask by Whittaker Riley. in the United States
Feb 04,2025

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Tutor-Verified Answer

Answer

The expression \(6y^{2}-24y+36\) factors to \(6(y^{2}-4y+6)\).

Solution

Factor the expression \( 6y^2-24y+36 \). Factor the expression by following steps: - step0: Factor: \(6y^{2}-24y+36\) - step1: Factor the expression: \(6\left(y^{2}-4y+6\right)\) The factored form of the expression \(6y^{2}-24y+36\) is \(6(y^{2}-4y+6)\).

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The Deep Dive

To factor the expression \( 6y^{2} - 24y + 36 \), start by looking for the greatest common factor (GCF). Here, the GCF is 6, so factor that out: \( 6(y^{2} - 4y + 6) \). Now, focus on factoring the quadratic \( y^{2} - 4y + 6 \). While it doesn't factor nicely into integers, you can complete the square or use the quadratic formula to find its roots, showing it’s not factorable over the reals. Now you have: \( 6(y^{2} - 4y + 6) \), and that's as simplified as it gets!

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