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Decrease 72 in a ratio of \( 7: 18 \) Increase 8 in a ratio of \( 5: 4 \)

Ask by Ortega Patel. in South Africa
Feb 03,2025

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To decrease 72 in a ratio of \(7:18\), divide 72 into 25 parts (7 + 18). Each part is \( \frac{72}{25} = 2.88 \). So, the first part is \(7 \times 2.88 = 20.16\) and the second part is \(18 \times 2.88 = 51.84\). To increase 8 in a ratio of \(5:4\), divide 8 into 9 parts (5 + 4). Each part is \( \frac{8}{9} \approx 0.8889 \). So, the first part is \(5 \times 0.8889 \approx 4.4445\) and the second part is \(4 \times 0.8889 \approx 3.5556\). **Summary:** - **Decreased 72:** 20.16 and 51.84 - **Increased 8:** Approximately 4.44 and 3.56

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To decrease 72 in a ratio of \( 7:18 \), you first add the parts of the ratio together: \( 7 + 18 = 25 \). Then, you find the portion to decrease: \( 72 \times \frac{7}{25} = 20.16 \). So, subtract that from 72 to get \( 72 - 20.16 = 51.84 \). For increasing 8 in the ratio of \( 5:4 \), again, add the parts of the ratio: \( 5 + 4 = 9 \). Now, find the increase: \( 8 \times \frac{5}{9} = 4.44 \), and add that to 8 to yield \( 8 + 4.44 = 12.44 \).

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