6) \( \left\{\begin{array}{l}y=-5 \\ 8 x+5 y=-17\end{array}\right. \)

To solve this system of equations, start by substituting the value of \(y\) from the first equation into the second equation. Since \(y = -5\), plug this into \(8x + 5y = -17\): \[ 8x + 5(-5) = -17 \\ 8x - 25 = -17 \\ 8x = 8 \\ x = 1 \] Thus, the solution to the system is \(x = 1\) and \(y = -5\), or the point \((1, -5)\). When working with systems of equations, it's great to check your solution by substituting both values back into the original equations to ensure they hold true. In this case: 1. For \(y = -5\), it is already set. 2. Plugging \(x = 1\) and \(y = -5\) into the second equation, \(8(1) + 5(-5) = 8 - 25 = -17\), confirms our solution is indeed correct!