2. Simon is making wreaths to sell. He has 60 bows, 36 silk roses, and 48 silk carnations. He wants to put the same number of items on each wreath. All the items on a wreath will be the same type. How many items can Simon put on each wreath?

To determine the maximum number of items Simon can place on each wreath while ensuring that: 1. Each wreath contains only one type of item (bows, silk roses, or silk carnations). 2. The same number of items is used for each wreath. We need to find the **greatest common divisor (GCD)** of the quantities of each type of item Simon has. Simon has: - **60 bows** - **36 silk roses** - **48 silk carnations** **Step-by-Step Calculation:** 1. **Find the GCD of 60 and 36:** - 60 ÷ 36 = 1 with a remainder of 24 - 36 ÷ 24 = 1 with a remainder of 12 - 24 ÷ 12 = 2 with a remainder of 0 - **GCD(60, 36) = 12** 2. **Find the GCD of the result (12) and 48:** - 48 ÷ 12 = 4 with a remainder of 0 - **GCD(12, 48) = 12** The **GCD** of **60**, **36**, and **48** is **12**. This means Simon can place **12 items** on each wreath. **Verification:** - **Bows:** 60 ÷ 12 = 5 wreaths - **Silk Roses:** 36 ÷ 12 = 3 wreaths - **Silk Carnations:** 48 ÷ 12 = 4 wreaths So, Simon can create a total of 12 wreaths, each with 12 items of the same type. **Answer:** 12 items can be placed on each wreath.