Question
Diketahui kurva \( y=f(x) \) diperoleh dari menggeser kurva \( g(x)=4-x^{2} \) tiga satuan ke kanan dan satu satuan ke bawah. Kurva \( g(x) \) memotong sumbu \( y \) di titik... \( \begin{array}{ll}\text { (A) }(0,4) & \text { (D) }(2,0) \\ \text { (B) }(0,-4) & \text { (E) }(-2,0) \\ \text { (C) }(0,0) & \end{array} \)
Ask by Williams Hammond.
Feb 16,2025 00:45
UpStudy AI Solution
Tutor-Verified Answer
Answer
Kurva \( g(x) = 4 - x^2 \) memotong sumbu \( y \) di titik \( (0,4) \).
Solution
Untuk menentukan titik potong kurva g(x)=4 − x² dengan sumbu y, kita substitusikan x = 0 ke dalam persamaan.
g(0) = 4 − (0)² = 4
Jadi, kurva memotong sumbu y di titik (0,4).
Jawaban yang benar: (A) (0,4).
Answered by UpStudy AI and reviewed by a Professional Tutor
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Simplify this solution Extra Insights
Mari kita analisis kurva \( g(x) = 4 - x^2 \) untuk mencari titik potongnya dengan sumbu \( y \). Titik potong dengan sumbu \( y \) terjadi saat \( x = 0 \).
Jadi, kita substitusi \( x = 0 \) ke dalam persamaan:
\[
g(0) = 4 - (0)^2 = 4
\]
Sehingga, kurva \( g(x) \) memotong sumbu \( y \) di titik \( (0, 4) \). Jadi, jawabannya adalah \( \text{(A) }(0,4) \).
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