Question
Balance the following equations and write the corresponding ionic and net ionic equations (if appropriate). (a) \( \mathrm{CH}_{3} \mathrm{COOH}(a q)+\mathrm{KOH}(a q) \longrightarrow \) (b) \( \mathrm{H}_{2} \mathrm{CO}_{3}(a q)+\mathrm{NaOH}(a q) \longrightarrow \) (c) \( \mathrm{HNO}_{3}(a q)+\mathrm{Ba}(\mathrm{OH})_{2}(a q) \longrightarrow \)
Ask by Welch Pierce.
Feb 11,2025 00:32
UpStudy AI Solution
Tutor-Verified Answer
Answer
(a) CH₃COOH (aq) + KOH (aq) → CH₃COOK (aq) + H₂O (l)
- **Complete Ionic Equation:**
CH₃COOH (aq) + K⁺ (aq) + OH⁻ (aq) → CH₃COO⁻ (aq) + K⁺ (aq) + H₂O (l)
- **Net Ionic Equation:**
CH₃COOH (aq) + OH⁻ (aq) → CH₃COO⁻ (aq) + H₂O (l)
(b) H₂CO₃ (aq) + NaOH (aq) → NaHCO₃ (aq) + H₂O (l)
- **Complete Ionic Equation:**
H₂CO₃ (aq) + Na⁺ (aq) + OH⁻ (aq) → Na⁺ (aq) + HCO₃⁻ (aq) + H₂O (l)
- **Net Ionic Equation:**
H₂CO₃ (aq) + OH⁻ (aq) → HCO₃⁻ (aq) + H₂O (l)
(c) 2 HNO₃ (aq) + Ba(OH)₂ (aq) → Ba(NO₃)₂ (aq) + 2 H₂O (l)
- **Complete Ionic Equation:**
2 H⁺ (aq) + 2 NO₃⁻ (aq) + Ba²⁺ (aq) + 2 OH⁻ (aq) → Ba²⁺ (aq) + 2 NO₃⁻ (aq) + 2 H₂O (l)
- **Net Ionic Equation:**
2 H⁺ (aq) + 2 OH⁻ (aq) → 2 H₂O (l)
(Simplified to: H⁺ (aq) + OH⁻ (aq) → H₂O (l))
Solution
Below are the balanced molecular equations along with their complete (total) ionic and net ionic equations.
──────────────────────────────
(a) Reaction: CH₃COOH (aq) + KOH (aq) → CH₃COOK (aq) + H₂O (l)
• Molecular Equation:
CH₃COOH (aq) + KOH (aq) → CH₃COOK (aq) + H₂O (l)
• Complete Ionic Equation:
CH₃COOH (aq) + K⁺ (aq) + OH⁻ (aq) → CH₃COO⁻ (aq) + K⁺ (aq) + H₂O (l)
(Note: Acetic acid is a weak acid and remains in its molecular form.)
• Net Ionic Equation:
CH₃COOH (aq) + OH⁻ (aq) → CH₃COO⁻ (aq) + H₂O (l)
(Canceled spectator ion: K⁺)
──────────────────────────────
(b) Reaction: H₂CO₃ (aq) + NaOH (aq) → NaHCO₃ (aq) + H₂O (l)
• Molecular Equation:
H₂CO₃ (aq) + NaOH (aq) → NaHCO₃ (aq) + H₂O (l)
(This represents the neutralization of one acidic proton; carbonic acid is diprotic, so further neutralization is possible.)
• Complete Ionic Equation:
H₂CO₃ (aq) + Na⁺ (aq) + OH⁻ (aq) → Na⁺ (aq) + HCO₃⁻ (aq) + H₂O (l)
(Again, H₂CO₃ is a weak acid and is not dissociated.)
• Net Ionic Equation:
H₂CO₃ (aq) + OH⁻ (aq) → HCO₃⁻ (aq) + H₂O (l)
(Canceled spectator ion: Na⁺)
──────────────────────────────
(c) Reaction: HNO₃ (aq) + Ba(OH)₂ (aq) → Ba(NO₃)₂ (aq) + H₂O (l)
Since barium hydroxide gives 2 OH⁻ per formula unit, two moles of nitric acid are required.
• Molecular Equation:
2 HNO₃ (aq) + Ba(OH)₂ (aq) → Ba(NO₃)₂ (aq) + 2 H₂O (l)
• Complete Ionic Equation:
2 H⁺ (aq) + 2 NO₃⁻ (aq) + Ba²⁺ (aq) + 2 OH⁻ (aq) →
Ba²⁺ (aq) + 2 NO₃⁻ (aq) + 2 H₂O (l)
(HNO₃ and Ba(OH)₂ are strong electrolytes and are fully dissociated.)
• Net Ionic Equation:
2 H⁺ (aq) + 2 OH⁻ (aq) → 2 H₂O (l)
(Spectator ions Ba²⁺ and NO₃⁻ are canceled.)
This can also be written in its simplest form as:
H⁺ (aq) + OH⁻ (aq) → H₂O (l)
if one recognizes that the equation is the basic acid–base neutralization process.
──────────────────────────────
These are the balanced equations with their corresponding ionic and net ionic forms.
Answered by UpStudy AI and reviewed by a Professional Tutor
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Simplify this solution Extra Insights
Let's balance each of the chemical equations and then write the ionic and net ionic equations where applicable.
### (a)
**Balanced Equation**:
\(\mathrm{CH}_{3} \mathrm{COOH}(aq) + \mathrm{KOH}(aq) \rightarrow \mathrm{CH}_{3} \mathrm{COOK}(aq) + \mathrm{H}_{2}\mathrm{O}(l)\)
**Ionic Equation**:
\(\mathrm{CH}_{3} \mathrm{COOH}(aq) + \mathrm{K}^+(aq) + \mathrm{OH}^-(aq) \rightarrow \mathrm{CH}_{3} \mathrm{COOK}(aq) + \mathrm{H}_{2}\mathrm{O}(l)\)
**Net Ionic Equation**:
\(\mathrm{CH}_{3} \mathrm{COOH}(aq) + \mathrm{OH}^-(aq) \rightarrow \mathrm{CH}_{3} \mathrm{COO}^-(aq) + \mathrm{H}_{2}\mathrm{O}(l)\)
---
### (b)
**Balanced Equation**:
\(\mathrm{H}_{2} \mathrm{CO}_{3}(aq) + 2\mathrm{NaOH}(aq) \rightarrow \mathrm{Na}_{2}\mathrm{CO}_{3}(aq) + 2\mathrm{H}_{2}\mathrm{O}(l)\)
**Ionic Equation**:
\(\mathrm{H}_{2} \mathrm{CO}_{3}(aq) + 2\mathrm{Na}^+(aq) + 2\mathrm{OH}^-(aq) \rightarrow \mathrm{Na}_{2}\mathrm{CO}_{3}(aq) + 2\mathrm{H}_{2}\mathrm{O}(l)\)
**Net Ionic Equation**:
\(\mathrm{H}_{2} \mathrm{CO}_{3}(aq) + 2\mathrm{OH}^-(aq) \rightarrow \mathrm{CO}_{3}^{2-}(aq) + 2\mathrm{H}_{2}\mathrm{O}(l)\)
---
### (c)
**Balanced Equation**:
\(\mathrm{HNO}_{3}(aq) + \mathrm{Ba(OH)}_{2}(aq) \rightarrow \mathrm{Ba(NO}_{3)}_{2}(aq) + 2\mathrm{H}_{2}\mathrm{O}(l)\)
**Ionic Equation**:
\(\mathrm{H}^+(aq) + \mathrm{NO}_{3}^-(aq) + \mathrm{Ba}^{2+}(aq) + 2\mathrm{OH}^-(aq) \rightarrow \mathrm{Ba(NO}_{3)}_{2}(aq) + 2\mathrm{H}_{2}\mathrm{O}(l)\)
**Net Ionic Equation**:
\(\mathrm{H}^+(aq) + \mathrm{OH}^-(aq) \rightarrow \mathrm{H}_{2}\mathrm{O}(l)\)
Feel free to ask if you need more help or any further clarifications!
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