Question
Balance the following equations and write the
corresponding ionic and net ionic equations (if
appropriate).
(a) \( \mathrm{CH}_{3} \mathrm{COOH}(a q)+\mathrm{KO

Balance the following equations and write the corresponding ionic and net ionic equations (if appropriate). (a) \( \mathrm{CH}_{3} \mathrm{COOH}(a q)+\mathrm{KOH}(a q) \longrightarrow \) (b) \( \mathrm{H}_{2} \mathrm{CO}_{3}(a q)+\mathrm{NaOH}(a q) \longrightarrow \) (c) \( \mathrm{HNO}_{3}(a q)+\mathrm{Ba}(\mathrm{OH})_{2}(a q) \longrightarrow \)

Ask by Welch Pierce.
Feb 11,2025 00:32

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Tutor-Verified Answer

Answer

(a) CH₃COOH (aq) + KOH (aq) → CH₃COOK (aq) + H₂O (l) - **Complete Ionic Equation:** CH₃COOH (aq) + K⁺ (aq) + OH⁻ (aq) → CH₃COO⁻ (aq) + K⁺ (aq) + H₂O (l) - **Net Ionic Equation:** CH₃COOH (aq) + OH⁻ (aq) → CH₃COO⁻ (aq) + H₂O (l) (b) H₂CO₃ (aq) + NaOH (aq) → NaHCO₃ (aq) + H₂O (l) - **Complete Ionic Equation:** H₂CO₃ (aq) + Na⁺ (aq) + OH⁻ (aq) → Na⁺ (aq) + HCO₃⁻ (aq) + H₂O (l) - **Net Ionic Equation:** H₂CO₃ (aq) + OH⁻ (aq) → HCO₃⁻ (aq) + H₂O (l) (c) 2 HNO₃ (aq) + Ba(OH)₂ (aq) → Ba(NO₃)₂ (aq) + 2 H₂O (l) - **Complete Ionic Equation:** 2 H⁺ (aq) + 2 NO₃⁻ (aq) + Ba²⁺ (aq) + 2 OH⁻ (aq) → Ba²⁺ (aq) + 2 NO₃⁻ (aq) + 2 H₂O (l) - **Net Ionic Equation:** 2 H⁺ (aq) + 2 OH⁻ (aq) → 2 H₂O (l) (Simplified to: H⁺ (aq) + OH⁻ (aq) → H₂O (l))

Solution

Below are the balanced molecular equations along with their complete (total) ionic and net ionic equations. ────────────────────────────── (a) Reaction: CH₃COOH (aq) + KOH (aq) → CH₃COOK (aq) + H₂O (l) • Molecular Equation:   CH₃COOH (aq) + KOH (aq) → CH₃COOK (aq) + H₂O (l) • Complete Ionic Equation:   CH₃COOH (aq) + K⁺ (aq) + OH⁻ (aq) → CH₃COO⁻ (aq) + K⁺ (aq) + H₂O (l)   (Note: Acetic acid is a weak acid and remains in its molecular form.) • Net Ionic Equation:   CH₃COOH (aq) + OH⁻ (aq) → CH₃COO⁻ (aq) + H₂O (l)   (Canceled spectator ion: K⁺) ────────────────────────────── (b) Reaction: H₂CO₃ (aq) + NaOH (aq) → NaHCO₃ (aq) + H₂O (l) • Molecular Equation:   H₂CO₃ (aq) + NaOH (aq) → NaHCO₃ (aq) + H₂O (l)   (This represents the neutralization of one acidic proton; carbonic acid is diprotic, so further neutralization is possible.) • Complete Ionic Equation:   H₂CO₃ (aq) + Na⁺ (aq) + OH⁻ (aq) → Na⁺ (aq) + HCO₃⁻ (aq) + H₂O (l)   (Again, H₂CO₃ is a weak acid and is not dissociated.) • Net Ionic Equation:   H₂CO₃ (aq) + OH⁻ (aq) → HCO₃⁻ (aq) + H₂O (l)   (Canceled spectator ion: Na⁺) ────────────────────────────── (c) Reaction: HNO₃ (aq) + Ba(OH)₂ (aq) → Ba(NO₃)₂ (aq) + H₂O (l) Since barium hydroxide gives 2 OH⁻ per formula unit, two moles of nitric acid are required. • Molecular Equation:   2 HNO₃ (aq) + Ba(OH)₂ (aq) → Ba(NO₃)₂ (aq) + 2 H₂O (l) • Complete Ionic Equation:   2 H⁺ (aq) + 2 NO₃⁻ (aq) + Ba²⁺ (aq) + 2 OH⁻ (aq) →    Ba²⁺ (aq) + 2 NO₃⁻ (aq) + 2 H₂O (l)   (HNO₃ and Ba(OH)₂ are strong electrolytes and are fully dissociated.) • Net Ionic Equation:   2 H⁺ (aq) + 2 OH⁻ (aq) → 2 H₂O (l)   (Spectator ions Ba²⁺ and NO₃⁻ are canceled.)   This can also be written in its simplest form as:    H⁺ (aq) + OH⁻ (aq) → H₂O (l)   if one recognizes that the equation is the basic acid–base neutralization process. ────────────────────────────── These are the balanced equations with their corresponding ionic and net ionic forms.

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Let's balance each of the chemical equations and then write the ionic and net ionic equations where applicable. ### (a) **Balanced Equation**: \(\mathrm{CH}_{3} \mathrm{COOH}(aq) + \mathrm{KOH}(aq) \rightarrow \mathrm{CH}_{3} \mathrm{COOK}(aq) + \mathrm{H}_{2}\mathrm{O}(l)\) **Ionic Equation**: \(\mathrm{CH}_{3} \mathrm{COOH}(aq) + \mathrm{K}^+(aq) + \mathrm{OH}^-(aq) \rightarrow \mathrm{CH}_{3} \mathrm{COOK}(aq) + \mathrm{H}_{2}\mathrm{O}(l)\) **Net Ionic Equation**: \(\mathrm{CH}_{3} \mathrm{COOH}(aq) + \mathrm{OH}^-(aq) \rightarrow \mathrm{CH}_{3} \mathrm{COO}^-(aq) + \mathrm{H}_{2}\mathrm{O}(l)\) --- ### (b) **Balanced Equation**: \(\mathrm{H}_{2} \mathrm{CO}_{3}(aq) + 2\mathrm{NaOH}(aq) \rightarrow \mathrm{Na}_{2}\mathrm{CO}_{3}(aq) + 2\mathrm{H}_{2}\mathrm{O}(l)\) **Ionic Equation**: \(\mathrm{H}_{2} \mathrm{CO}_{3}(aq) + 2\mathrm{Na}^+(aq) + 2\mathrm{OH}^-(aq) \rightarrow \mathrm{Na}_{2}\mathrm{CO}_{3}(aq) + 2\mathrm{H}_{2}\mathrm{O}(l)\) **Net Ionic Equation**: \(\mathrm{H}_{2} \mathrm{CO}_{3}(aq) + 2\mathrm{OH}^-(aq) \rightarrow \mathrm{CO}_{3}^{2-}(aq) + 2\mathrm{H}_{2}\mathrm{O}(l)\) --- ### (c) **Balanced Equation**: \(\mathrm{HNO}_{3}(aq) + \mathrm{Ba(OH)}_{2}(aq) \rightarrow \mathrm{Ba(NO}_{3)}_{2}(aq) + 2\mathrm{H}_{2}\mathrm{O}(l)\) **Ionic Equation**: \(\mathrm{H}^+(aq) + \mathrm{NO}_{3}^-(aq) + \mathrm{Ba}^{2+}(aq) + 2\mathrm{OH}^-(aq) \rightarrow \mathrm{Ba(NO}_{3)}_{2}(aq) + 2\mathrm{H}_{2}\mathrm{O}(l)\) **Net Ionic Equation**: \(\mathrm{H}^+(aq) + \mathrm{OH}^-(aq) \rightarrow \mathrm{H}_{2}\mathrm{O}(l)\) Feel free to ask if you need more help or any further clarifications!

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