1 Solve the equation \( -0.4 \cos t+1=1.3 \) where \( 301^{\circ} \leq t \leq 700^{\circ} \).
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To solve the equation \( -0.4 \cos t + 1 = 1.3 \), we first isolate the cosine term: \[ -0.4 \cos t = 1.3 - 1 \] \[ -0.4 \cos t = 0.3 \] \[ \cos t = -\frac{0.3}{0.4} = -0.75 \] Now we need to find the angles \( t \) for which \( \cos t = -0.75 \). The cosine function is negative in the second and third quadrants. To find the reference angle, we use: \[ \theta = \cos^{-1}(0.75) \approx 41.41^{\circ} \] Next, we find the angles in the specified quadrants: - In the second quadrant: \[ t = 180^{\circ} - 41.41^{\circ} \approx 138.59^{\circ} \] - In the third quadrant: \[ t = 180^{\circ} + 41.41^{\circ} \approx 221.41^{\circ} \] However, we need to find all possible solutions for \( t \) in the range \( 301^{\circ} \leq t \leq 700^{\circ} \). We can add \( 360^{\circ} \) to both angles to get additional solutions: For \( t = 138.59^{\circ} \): \[ t = 138.59^{\circ} + 360^{\circ} \approx 498.59^{\circ} \] For \( t = 221.41^{\circ} \): \[ t = 221.41^{\circ} + 360^{\circ} \approx 581.41^{\circ} \] Now we summarize the solutions that fall within the given range: \[ t \approx 498.59^{\circ}, \quad t \approx 581.41^{\circ} \] Thus, the final solutions are \( t \approx 498.59^{\circ} \) and \( t \approx 581.41^{\circ} \).