The graph of which function has the same end benavior as the graph of $$ f(x)=-x^{2} $$ ? $$ \begin{array}{l}h(x)=(x)=x^{4} \ h(x)=-x^{5} \ k(x)--x^{5}\end{array} $$

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To determine which function has the same end behavior as $$ f(x) = -x^2 $$, let's first analyze the end behavior of $$ f(x) $$.

### End Behavior of $$ f(x) = -x^2 $$
- **As $$ x 	o +\infty $$:** $$ f(x) 	o -\infty $$
- **As $$ x 	o -\infty $$:** $$ f(x) 	o -\infty $$

This means that for $$ f(x) = -x^2 $$, both ends of the graph point downward.

### Analyzing the Given Functions

1. **$$ h(x) = x^4 $$**
   - **Degree:** 4 (even)
   - **Leading Coefficient:** +1 (positive)
   - **End Behavior:**
     - As $$ x 	o +\infty $$, $$ h(x) 	o +\infty $$
     - As $$ x 	o -\infty $$, $$ h(x) 	o +\infty $$
   
   **Conclusion:** Both ends point upward. **Does not match** $$ f(x) $$.

2. **$$ h(x) = -x^5 $$**
   - **Degree:** 5 (odd)
   - **Leading Coefficient:** -1 (negative)
   - **End Behavior:**
     - As $$ x 	o +\infty $$, $$ h(x) 	o -\infty $$
     - As $$ x 	o -\infty $$, $$ h(x) 	o +\infty $$

**Conclusion:** One end points downward and the other upward. **Does not match** $$ f(x) $$.

3. **$$ k(x) = x^5 $$**
   - **Degree:** 5 (odd)
   - **Leading Coefficient:** +1 (positive)
   - **End Behavior:**
     - As $$ x 	o +\infty $$, $$ k(x) 	o +\infty $$
     - As $$ x 	o -\infty $$, $$ k(x) 	o -\infty $$

**Conclusion:** One end points upward and the other downward. **Does not match** $$ f(x) $$.

### Summary

None of the provided functions have both ends pointing downward like $$ f(x) = -x^2 $$. To have the same end behavior, you would need a **even-degree polynomial with a negative leading coefficient**, such as $$ g(x) = -x^4 $$. However, this function is not among the given options.

**Answer:** None of the listed functions share the same end behavior as $$ f(x) = -x^2 $$.
None of the given functions have the same end behavior as $$ f(x) = -x^2 $$.

The graph of which function has the same end benavior as the graph of ?

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