Question
A rental car company charges \( \$ 50 \) plus 25 cents per each mile driven. Part1. Which of the following could be used to model the total cost of the rental where \( m \) represents the miles driven. \( \begin{array}{l}C=2.5 m+50 \\ C=0.25 m+50 \\ C=25 m+50 \\ \text { Part 2. The total cost of driving } 400 \text { miles is; }\end{array} \)
Ask by May Stephens. in the United States
Feb 04,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
**Part 1:** The correct model for the total cost is \( C = 0.25m + 50 \).
**Part 2:** The total cost for driving 400 miles is \$150.
Solution
Let's break down the problem into its two parts.
---
### **Part 1: Modeling the Total Cost**
The rental car company's pricing structure is:
- **Base Fee:** \$50
- **Variable Fee:** \$0.25 per mile driven
To create a mathematical model where \( m \) represents the number of miles driven, we combine the base fee with the variable fee:
\[
\text{Total Cost} (C) = \text{Base Fee} + (\text{Cost per Mile} \times \text{Number of Miles})
\]
Substituting the given values:
\[
C = 0.25m + 50
\]
**Among the given options:**
1. \( C = 2.5m + 50 \) → This implies \$2.50 per mile, which is **incorrect**.
2. \( C = 0.25m + 50 \) → This correctly represents \$0.25 per mile, which is **correct**.
3. \( C = 25m + 50 \) → This implies \$25 per mile, which is **incorrect**.
**Correct Model:**
\[
C = 0.25m + 50
\]
---
### **Part 2: Calculating the Total Cost for 400 Miles**
Using the correct model from Part 1:
\[
C = 0.25m + 50
\]
Substitute \( m = 400 \) miles:
\[
C = 0.25 \times 400 + 50
\]
\[
C = 100 + 50
\]
\[
C = 150
\]
**Total Cost for 400 Miles:**
\[
\$150
\]
---
**Summary:**
1. **Model:** \( C = 0.25m + 50 \)
2. **Total Cost for 400 Miles:** \$150
Reviewed and approved by the UpStudy tutoring team
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Bonus Knowledge
The correct model to represent the total cost of the rental is \( C = 0.25m + 50 \) because the cost includes a base fee of \( \$50 \) plus \( 25 \) cents (or \( 0.25 \) dollars) for each mile driven. Now, for part 2, to find the total cost of driving 400 miles, you would substitute \( m = 400 \) into the equation: \[ C = 0.25(400) + 50 = 100 + 50 = 150. \] So, the total cost for driving \( 400 \) miles is \( \$150 \).