(2) $$ \left\{\begin{array}{l}6 x+5 y=23 \ -4 y+y=-11\end{array} ight. $$

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(2) $$ \left\{\begin{array}{l}6 x+5 y=23 \ -4 y+y=-11\end{array}ight. $$

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Solve the system of equations $$ 6x+5y=23;-4y+y=-11 $$.
Solve the system of equations by following steps:
- step0: Solve using the substitution method:
  $$\left\{ \begin{array}{l}6x+5y=23\-4y+y=-11\end{array}ight.$$
- step1: Calculate:
  $$\left\{ \begin{array}{l}6x+5y=23\-3y=-11\end{array}ight.$$
- step2: Solve the equation:
  $$\left\{ \begin{array}{l}6x+5y=23\y=\frac{11}{3}\end{array}ight.$$
- step3: Substitute the value of $$y:$$
  $$6x+5	imes \frac{11}{3}=23$$
- step4: Multiply the numbers:
  $$6x+\frac{55}{3}=23$$
- step5: Move the constant to the right side:
  $$6x=23-\frac{55}{3}$$
- step6: Subtract the numbers:
  $$6x=\frac{14}{3}$$
- step7: Multiply by the reciprocal:
  $$6x	imes \frac{1}{6}=\frac{14}{3}	imes \frac{1}{6}$$
- step8: Multiply:
  $$x=\frac{7}{9}$$
- step9: Calculate:
  $$\left\{ \begin{array}{l}x=\frac{7}{9}\y=\frac{11}{3}\end{array}ight.$$
- step10: Check the solution:
  $$\left\{ \begin{array}{l}x=\frac{7}{9}\y=\frac{11}{3}\end{array}ight.$$
- step11: Rewrite:
  $$\left(x,yight) = \left(\frac{7}{9},\frac{11}{3}ight)$$
La solución del sistema de ecuaciones es $$ (x,y) = \left(\frac{7}{9},\frac{11}{3}ight) $$ o en forma decimal $$ (x,y) = (0.\dot{7},3.\dot{6}) $$.
La solución del sistema de ecuaciones es $$ (x,y) = \left(\frac{7}{9},\frac{11}{3}ight) $$.

(2) \( \left\{\begin{array}{l}6 x+5 y=23 \\ -4 y+y=-11\end{array}\right. \)

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