c) \( \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Br}+\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CO}-\mathrm{K}+\left(\mathrm{CH}_{3}\right)_{3} \mathrm{COH} \)
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Bonus Knowledge
Let's stir up some fun chemistry here! The reaction you have written involves a brominated alkane, specifically 1-bromopropane (\( \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Br} \)), undergoing a nucleophilic substitution reaction. In this case, potassium tert-butoxide (\( \left(\mathrm{CH}_{3}\right)_{3} \mathrm{CO}-\mathrm{K} \)) is a strong base that can also act as a nucleophile to replace the bromine atom with a tert-butoxy group, leading to the formation of tert-butyl ether as your product. Additionally, this type of nucleophilic substitution reaction is instrumental in organic synthesis. It provides a pathway to create complex molecules which are key in medicinal chemistry, agrochemicals, and various industrial applications. So not only do you get to play with fun molecules, but you’re also contributing to fields that tackle real-world issues, such as developing new medications or advancing sustainable materials! Happy experimenting!