Question
13. Haley scored \( 93 \% \) on her first math test and \( 86 \% \) on her second test. What is her percent decrease from Test 1 to Test 2 to the nearest tenth? \( \% \)
Ask by Greene Bates. in the United States
Jan 26,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
Haley's percent decrease from Test 1 to Test 2 is 7.5%.
Solution
To calculate Haley's percent decrease from Test 1 to Test 2, you can use the following formula for percent decrease:
\[
\text{Percent Decrease} = \left( \frac{\text{Old Score} - \text{New Score}}{\text{Old Score}} \right) \times 100\%
\]
Plugging in Haley's scores:
\[
\text{Percent Decrease} = \left( \frac{93\% - 86\%}{93\%} \right) \times 100\%
\]
\[
\text{Percent Decrease} = \left( \frac{7}{93} \right) \times 100\% \approx 7.5269\%
\]
Rounded to the nearest tenth:
\[
\text{Percent Decrease} \approx 7.5\%
\]
**Answer:** 7.5 %
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Simplify this solution Mind Expander
To find Haley's percent decrease from her first test to her second test, we first calculate the decrease in her scores. The decrease in her score is \( 93\% - 86\% = 7\% \). Next, we divide the decrease by the original score (the score of the first test) and multiply by 100 to convert it to a percentage. So, the calculation looks like this: \[ \text{Percent decrease} = \left( \frac{7}{93} \right) \times 100 \approx 7.53\% \] Rounding to the nearest tenth, Haley's percent decrease is approximately \( 7.5\% \).
