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d. \( r=\frac{C}{2 r}+2 r+2 L \quad \) is \( r \) isolated?

Ask by Herrera Lang. in the United States
Feb 03,2025

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In the equation \( r = \frac{C}{2r} + 2r + 2L \), the variable \( r \) is **not isolated** because it appears on both sides and within a reciprocal term. To solve for \( r \), you need to perform additional algebraic steps, which results in a quadratic equation. Therefore, \( r \) is not isolated in its current form. **Simplified Answer:** \( r \) is not isolated in the equation \( r = \frac{C}{2r} + 2r + 2L \).

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Mind Expander

To isolate \( r \) in the equation \( r = \frac{C}{2r} + 2r + 2L \), you'll want to first move all terms involving \( r \) to one side. Subtract \( 2r \) from both sides and multiply through by \( 2r \) to eliminate the fraction, leading to a polynomial equation. Solving this will help you isolate \( r \). Watch out for potential complications, such as quadratic terms! When dealing with equations like this, common mistakes include mismanaging the distributive properties or forgetting to adjust each term when moving them. Always double-check your operations and be cautious with your signs. A little care goes a long way when isolating variables in equations!

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