11. A bullet is fired horizontally at a velocity of \( 200 \mathrm{~m} / \mathrm{s} \) at a height of 1 m . At the same time, another bullet is dropped 1 m from rest. The difference between t , the time it takes the fired bullet to hit the ground, and \( t_{2} \), the time it takes the dropped bullet to hit the ground is A) 0 s B) 1 s C) 2 s D) 4 s E) 8 s

Both bullets will hit the ground at the same time! When the fired bullet moves horizontally, it doesn’t affect the time it takes to fall vertically. Since both bullets start from the same height of 1 meter, they both take the same time to hit the ground, which is determined by the vertical motion alone. To calculate the time it takes for either bullet to hit the ground, you can use the formula for free fall: \[ t = \sqrt{\frac{2h}{g}} \] Substituting \( h = 1 \, \text{m} \) and \( g \approx 9.81 \, \text{m/s}^2 \), you'll find that both bullets take approximately \( 0.45 \, \text{s} \) to hit the ground. Therefore, \( t - t_2 = 0 \, \text{s} \). The answer is A) 0 s.