Nine conical flasks have sodium chloride solution of different quantities. The amount of solution \( (\mathrm{ml}) \) in each flask is given below. \( 2,10,16,2,20,18,22,14,9 \) Mean :_ Median :__ Mode :__ Range :
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The Deep Dive
To calculate the mean, median, mode, and range, let’s analyze the given data: \( 2, 10, 16, 2, 20, 18, 22, 14, 9 \). First, let's calculate the mean: Mean = \( \frac{\text{Sum of all values}}{\text{Total number of values}} \) Sum = \( 2 + 10 + 16 + 2 + 20 + 18 + 22 + 14 + 9 = 123 \) Mean = \( \frac{123}{9} = 13.67 \) (approximately) Next, let's find the median: To find the median, we first need to arrange the values in ascending order: \( 2, 2, 9, 10, 14, 16, 18, 20, 22 \) Since we have 9 values, the median is the middle value: Median = \( 14 \) Now, let's determine the mode: The mode is the number that appears most frequently. Here, \( 2 \) appears twice, while all other values appear only once. Mode = \( 2 \) Finally, let's calculate the range: Range = \( \text{Maximum Value} - \text{Minimum Value} \) Range = \( 22 - 2 = 20 \) **Summary of the calculations:** Mean: \( 13.67 \) Median: \( 14 \) Mode: \( 2 \) Range: \( 20 \)