Question
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The accompanying frequency polygon represents the number of a country’s residents below 100 years of age. Complete parts (a) through (f) below.
The class width is 10 .
(Type a whole number.)
There are 10 classes represented in the graph.
(Type a whole number.)
(b) What is the midpoint of the first class? What are the lowe
The midpoint of the first class is 5 .
(Type a whole number.)
The lower limit of the first class is 0 . The upper limit of the fi
(Type whole numbers.)
© What is the midpoint of the next to last class? What are th
The midpoint of the next to last class is

Ask by Chandler Vaughn. in Mexico
Dec 20,2024

Upstudy AI Solution

Tutor-Verified Answer

Answer

© What is the midpoint of the next to last class? What are the lower and upper limits of that class?
  • Midpoint of the next to last class: 85
  • Lower limit of the next to last class: 80
  • Upper limit of the next to last class: 90

Solution

© What is the midpoint of the next to last class? What are the lower and upper limits of that class?
  • Midpoint of the next to last class: 85
  • Lower limit of the next to last class: 80
  • Upper limit of the next to last class: 90
Explanation:
Given that each class has a width of 10 and there are 10 classes in total, the classes are structured as follows:
  1. 0 - 10 (Midpoint: 5)
  2. 10 - 20 (Midpoint: 15)
  3. 20 - 30 (Midpoint: 25)
  4. 30 - 40 (Midpoint: 35)
  5. 40 - 50 (Midpoint: 45)
  6. 50 - 60 (Midpoint: 55)
  7. 60 - 70 (Midpoint: 65)
  8. 70 - 80 (Midpoint: 75)
  9. 80 - 90 (Midpoint: 85) ← Next to Last Class
  10. 90 - 100 (Midpoint: 95)
Therefore, the next to last class is 80 - 90, with a midpoint of 85.

Answered by UpStudy AI and reviewed by a Professional Tutor

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Extra Insights

For the next-to-last class, you can find the midpoint by first identifying the class range. If the class width is 10 and you’re moving back from the final class (which would typically be 90-99 considering there are 10 classes), the next to last class would be 80-89. The midpoint is calculated by averaging the lower and upper limits: (80 + 89) / 2 = 84.5.
The lower limit of this class is 80, and the upper limit is 89. So, you can state: The midpoint of the next to last class is 84.5. The lower limit of this class is 80, and the upper limit is 89.

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