Question
Subtract. \( \begin{array}{r}8 y^{2}-6 y+5 \\ \frac{-\left(-2 y^{2}+6 y+9\right)}{} \\ \hline \frac{-\left(-2 y^{2}+6 y+9\right)}{\square}\end{array} \)
Ask by Young Cruz. in the United States
Feb 03,2025
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Tutor-Verified Answer
Answer
The result of the subtraction is \(10y^{2} - 12y - 4\).
Solution
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Beyond the Answer
To subtract \( -(-2y^2 + 6y + 9) \) from \( 8y^2 - 6y + 5 \), we first rewrite the expression: \[ 8y^2 - 6y + 5 + (2y^2 - 6y - 9). \] Now, we combine like terms: - The \(y^2\) terms: \(8y^2 + 2y^2 = 10y^2\) - The \(y\) terms: \(-6y - 6y = -12y\) - The constant terms: \(5 - 9 = -4\) Putting it all together gives us: \[ 10y^2 - 12y - 4. \] So, the final result of the subtraction is \( 10y^2 - 12y - 4 \).