Find the axis of symmatry Find the vertexy $$ y=x^{2}+6 x+5 $$

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To find the axis of symmetry and the vertex of the parabola given by the equation $$ y = x^2 + 6x + 5 $$, we can use the following steps:

1. **Axis of Symmetry:**
   The axis of symmetry of a parabola in the form $$ y = ax^2 + bx + c $$ is given by the equation $$ x = -\frac{b}{2a} $$.

2. **Vertex:**
   The vertex of a parabola in the form $$ y = ax^2 + bx + c $$ is given by the coordinates $$ \left(-\frac{b}{2a}, f\left(-\frac{b}{2a}ight)ight) $$, where $$ f(x) = ax^2 + bx + c $$.

Let's calculate the axis of symmetry and the vertex of the given parabola.
Calculate the value by following steps:
- step0: Calculate:
  $$\frac{-6}{\left(2	imes 1ight)}$$
- step1: Remove the parentheses:
  $$\frac{-6}{2	imes 1}$$
- step2: Calculate:
  $$-\frac{6}{2	imes 1}$$
- step3: Rewrite the expression:
  $$-\frac{6}{2}$$
- step4: Reduce the fraction:
  $$-3$$
The axis of symmetry is $$ x = -3 $$.

Now, let's find the vertex of the parabola.
Calculate the value by following steps:
- step0: Calculate:
  $$1	imes \left(-3ight)^{2}+6\left(-3ight)+5$$
- step1: Multiply:
  $$\left(-3ight)^{2}+6\left(-3ight)+5$$
- step2: Multiply the numbers:
  $$\left(-3ight)^{2}-18+5$$
- step3: Evaluate the power:
  $$9-18+5$$
- step4: Calculate:
  $$-4$$
The vertex of the parabola is at the point $$ (-3, -4) $$.

Therefore, the axis of symmetry is $$ x = -3 $$ and the vertex is at the point $$ (-3, -4) $$.
The axis of symmetry is $$ x = -3 $$ and the vertex is at $$ (-3, -4) $$.

Find the axis of symmatry Find the vertexy \( y=x^{2}+6 x+5 \)

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