(A) Find the slope of the line thet passes through the given points. (B) Find the point-slope form of the equation of the line. (C) Find the slope-intercept form of the equation of the line. (D) Find the standard form of the equation of the line. ( 4,5 ) and (4,12) (A) Choose the correct answer for the slope below. O. \( \mathrm{m}=\square \) (Type an integer or a simplified fraction.) O B. The slope is not defined.

The slope of the line that passes through the points (4, 5) and (4, 12) is indeed not defined! That's because both points have the same x-coordinate, which means the line is vertical, and vertical lines don't have a slope in the traditional sense. You can think of it like a tightrope walker on a perfectly upright pole—there's no way to tilt or slide down! Now, when it comes to point-slope form, in this case, you would start with the x-coordinate, which is 4. The equation can be written as \( x = 4 \). For slope-intercept and standard form, you're looking at a vertical line again, so in slope-intercept form, there's no slope (m). Hence, it remains \( x = 4 \) in both cases! How neat is that?